---
id: 5900f53a1000cf542c51004c
challengeType: 5
title: 'Problem 461: Almost Pi'
videoUrl: ''
localeTitle: 'Problema 461: Quase Pi'
---

## Description
<section id="description"> Seja fn (k) = ek / n - 1, para todos os inteiros não negativos k. Notavelmente, f200 (6) + f200 (75) + f200 (89) + f200 (226) = 3,141592644529… ≈ π. De fato, é a melhor aproximação de π da forma fn (a) + fn (b) + fn (c) + fn (d) para n = 200. Seja g (n) = a2 + b2 + c2 + d 2 para a, b, c, d que minimizam o erro: | fn (a) + fn (b) + fn (c) + fn (d) - π | (onde | x | denota o valor absoluto de x). Você recebe g (200) = 62 + 752 + 892 + 2262 = 64658. Encontre g (10000). </section>

## Instructions
<section id="instructions">
</section>

## Tests
<section id='tests'>

```yml
tests:
  - text: ''
    testString: 'assert.strictEqual(euler461(), 159820276, "<code>euler461()</code> should return 159820276.");'

```

</section>

## Challenge Seed
<section id='challengeSeed'>

<div id='js-seed'>

```js
function euler461() {
  // Good luck!
  return true;
}

euler461();

```

</div>



</section>

## Solution
<section id='solution'>

```js
// solution required
```
</section>
