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---
id: 5900f3a91000cf542c50febc
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title: 'Problema 61: Numeri ciclici figurati'
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challengeType: 5
forumTopicId: 302173
dashedName: problem-61-cyclical-figurate-numbers
---
# --description--
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Numeri triangolari, quadrati, pentagonali, esagonali, eptagonali e ottagonali sono tutti numeri che sono figurati (poligonali) e sono generati dalle seguenti formule:
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| Tipo di numero | Formula | Sequenza |
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| -------------- | ----------------------------- | --------------------- |
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| Triangolare | $P_3(n) = \frac{n(n+1)}{2}$ | 1, 3, 6, 10, 15, ... |
| Quadrato | $P_4(n) = n^2$ | 1, 4, 9, 16, 25, ... |
| Pentagonale | $P_5(n) = \frac{n(3n− 1)}2$ | 1, 5, 12, 22, 35, ... |
| Esagonale | $P_6(n) = n(2n− 1)$ | 1, 6, 15, 28, 45, ... |
| Eptagonale | $P_7(n) = \frac{n(5n− 3)}{2}$ | 1, 7, 18, 34, 55, ... |
| Ottagonale | $P_8(n) = n(3n− 2)$ | 1, 8, 21, 40, 65, ... |
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Il set ordinato nei numeri a 4 cifre: 8128, 2882, 8281, ha tre interessanti proprietà.
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1. Il set è ciclico, in quanto le ultime due cifre di ogni numero sono le prime due cifre del seguente (incluso l'ultimo numero con il primo).
2. Ogni tipo poligonale: triangolare ($P_3(127) = 8128$), quadrato ($P_4(91) = 8281$), e pentagonale ($P_5(44) = 2882$), è rappresentato da un diverso numero nel set.
3. Questo è l'unico set con numeri a quattro cifre con questa proprietà.
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Trova la somma di tutti i numeri in set ordinati di `n` numeri ciclici a quattro cifre per cui ognuno dei tipi poligonali da $P_3$ a $P_{n + 2}$ è rappresentato da un diverso numero nel set.
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# --hints--
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`cyclicalFigurateNums(3)` dovrebbe restituire un numero.
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```js
assert(typeof cyclicalFigurateNums(3) === 'number');
```
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`cyclicalFigurateNums(3)` dovrebbe restituire `19291` .
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```js
assert.strictEqual(cyclicalFigurateNums(3), 19291);
```
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`cyclicalFigurateNums(4)` dovrebbe restituire `28684` .
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```js
assert.strictEqual(cyclicalFigurateNums(4), 28684);
```
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`cyclicalFigurateNums(5)` dovrebbe restituire `76255` .
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```js
assert.strictEqual(cyclicalFigurateNums(5), 76255);
```
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`cyclicalFigurateNums(6)` dovrebbe restituire `28684` .
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```js
assert.strictEqual(cyclicalFigurateNums(6), 28684);
```
# --seed--
## --seed-contents--
```js
function cyclicalFigurateNums(n) {
return true;
}
cyclicalFigurateNums(3);
```
# --solutions--
```js
function cyclicalFigurateNums(n) {
function getChains(chain, n, numberTypes, numsExcludingLastNeededType) {
if (chain.length === n) {
return [chain];
}
const nextNumbers = getNextNumbersInChain(
chain[chain.length - 1],
numsExcludingLastNeededType
);
const chains = [];
for (let j = 0; j < nextNumbers.length ; j + + ) {
const nextNumber = nextNumbers[j];
if (chain.indexOf(nextNumber) === -1) {
const nextChain = [...chain, nextNumber];
chains.push(
...getChains(nextChain, n, numberTypes, numsExcludingLastNeededType)
);
}
}
return chains;
}
function getNextNumbersInChain(num, numsExcludingLastNeededType) {
const results = [];
const beginning = num % 100;
numsExcludingLastNeededType.forEach(number => {
if (Math.floor(number / 100) === beginning) {
results.push(number);
}
});
return results;
}
function fillNumberTypes(n, numberTypes, numsExcludingLastNeededType) {
const [, lastTypeCheck, lastTypeArr] = numberTypes[n - 1];
for (let i = 1000; i < = 9999; i++) {
for (let j = 0; j < n - 1 ; j + + ) {
const [, typeCheck, typeArr] = numberTypes[j];
if (typeCheck(i)) {
typeArr.push(i);
numsExcludingLastNeededType.add(i);
}
}
if (lastTypeCheck(i)) {
lastTypeArr.push(i);
}
}
}
function isCyclicalChain(chain, n, numberTypes) {
const numberTypesInChain = getNumberTypesInChain(chain, numberTypes);
if (!isChainAllowed(numberTypesInChain, n)) {
return false;
}
const isChainCyclic =
Math.floor(chain[0] / 100) === chain[chain.length - 1] % 100;
return isChainCyclic;
}
function getNumberTypesInChain(chain, numberTypes) {
const numbersInChain = {};
for (let i = 0; i < numberTypes.length ; i + + ) {
const numberTypeName = numberTypes[i][0];
numbersInChain[numberTypeName] = [];
}
for (let i = 0; i < chain.length ; i + + ) {
for (let j = 0; j < n ; j + + ) {
const [typeName, , typeNumbers] = numberTypes[j];
const typeNumbersInChain = numbersInChain[typeName];
if (typeNumbers.indexOf(chain[i]) !== -1) {
typeNumbersInChain.push(chain[i]);
}
}
}
return numbersInChain;
}
function isChainAllowed(numberTypesInChain, n) {
for (let i = 0; i < n ; i + + ) {
const typeName = numberTypes[i][0];
const isNumberWithTypeInChain = numberTypesInChain[typeName].length > 0;
if (!isNumberWithTypeInChain) {
return false;
}
for (let j = i + 1; j < n ; j + + ) {
const otherTypeName = numberTypes[j][0];
if (
isNumberRepeatedAsOnlyNumberInTwoTypes(
numberTypesInChain[typeName],
numberTypesInChain[otherTypeName]
)
) {
return false;
}
}
}
return true;
}
function isNumberRepeatedAsOnlyNumberInTwoTypes(
typeNumbers,
otherTypeNumbers
) {
return (
typeNumbers.length === 1 & &
otherTypeNumbers.length === 1 & &
typeNumbers[0] === otherTypeNumbers[0]
);
}
function isTriangle(num) {
return ((8 * num + 1) * * 0.5 - 1) % 2 === 0;
}
function isSquare(num) {
return num ** 0.5 === parseInt(num ** 0.5, 10);
}
function isPentagonal(num) {
return ((24 * num + 1) * * 0.5 + 1) % 6 === 0;
}
function isHexagonal(num) {
return ((8 * num + 1) * * 0.5 + 1) % 4 === 0;
}
function isHeptagonal(num) {
return ((40 * num + 9) * * 0.5 + 3) % 10 === 0;
}
function isOctagonal(num) {
return ((3 * num + 1) * * 0.5 + 1) % 3 === 0;
}
const numberTypes = [
['triangle', isTriangle, []],
['square', isSquare, []],
['pentagonal', isPentagonal, []],
['hexagonal', isHexagonal, []],
['heptagonal', isHeptagonal, []],
['octagonal', isOctagonal, []]
];
const numsExcludingLastNeededType = new Set();
fillNumberTypes(n, numberTypes, numsExcludingLastNeededType);
const nNumberChains = [];
const [, , lastType] = numberTypes[n - 1];
for (let i = 0; i < lastType.length ; i + + ) {
const startOfChain = lastType[i];
nNumberChains.push(
...getChains([startOfChain], n, numberTypes, numsExcludingLastNeededType)
);
}
const cyclicalChains = nNumberChains.filter(chain =>
isCyclicalChain(chain, n, numberTypes)
);
let sum = 0;
for (let i = 0; i < cyclicalChains.length ; i + + ) {
for (let j = 0; j < cyclicalChains [ 0 ] . length ; j + + ) {
sum += cyclicalChains[i][j];
}
}
return sum;
}
```