2018-09-30 23:01:58 +01:00
										 
									 
								 
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								id: 5900f3711000cf542c50fe84
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								title: 'Problem 5: Smallest multiple'
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											2020-11-27 19:02:05 +01:00
										 
									 
								 
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								challengeType: 5
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											2019-08-05 09:17:33 -07:00
										 
									 
								 
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								forumTopicId: 302160
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											2021-01-13 03:31:00 +01:00
										 
									 
								 
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								dashedName: problem-5-smallest-multiple
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											2018-09-30 23:01:58 +01:00
										 
									 
								 
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								---
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											2020-11-27 19:02:05 +01:00
										 
									 
								 
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								# --description--
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											2018-09-30 23:01:58 +01:00
										 
									 
								 
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								2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder.
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								What is the smallest positive number that is evenly divisible by all of the numbers from 1 to `n`?
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								# --hints--
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								`smallestMult(5)` should return a number.
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											2020-11-27 19:02:05 +01:00
										 
									 
								 
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								```js
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								assert(typeof smallestMult(5) === 'number');
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								```
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								`smallestMult(5)` should return 60.
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								```js
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								assert.strictEqual(smallestMult(5), 60);
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								```
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								`smallestMult(7)` should return 420.
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								```js
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								assert.strictEqual(smallestMult(7), 420);
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								```
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								`smallestMult(10)` should return 2520.
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								```js
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								assert.strictEqual(smallestMult(10), 2520);
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								```
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								`smallestMult(13)` should return 360360.
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								```js
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								assert.strictEqual(smallestMult(13), 360360);
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								```
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											2020-09-15 09:57:40 -07:00
										 
									 
								 
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								`smallestMult(20)` should return 232792560.
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								```js
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								assert.strictEqual(smallestMult(20), 232792560);
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								```
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								# --seed--
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								## --seed-contents--
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								```js
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								function smallestMult(n) {
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								  return true;
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								}
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								smallestMult(20);
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								```
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								# --solutions--
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								```js
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								function smallestMult(n){
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								  function gcd(a, b) {
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								    return b === 0 ? a : gcd(b, a%b); // Euclidean algorithm
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								  }
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								  function lcm(a, b) {
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								    return a * b / gcd(a, b);
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								  }
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								  var result = 1;
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								  for(var i = 2; i <= n; i++) {
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								    result = lcm(result, i);
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								  }
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								  return result;
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								}
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								```
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