2018-10-10 18:03:03 -04:00
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---
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id: 594810f028c0303b75339ad1
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2020-12-16 00:37:30 -07:00
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title: 快乐的数字
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2018-10-10 18:03:03 -04:00
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challengeType: 5
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videoUrl: ''
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2021-01-13 03:31:00 +01:00
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dashedName: happy-numbers
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2018-10-10 18:03:03 -04:00
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---
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2020-12-16 00:37:30 -07:00
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# --description--
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<p>幸福的数字由以下过程定义: </p><p>从任何正整数开始,将数字替换为其数字的平方和,并重复该过程直到数字等于1(它将保持不变),或者它在一个不包括1的循环中无休止地循环。这些数字这个过程在1结束的是幸福的数字,而那些不以1结尾的数字是不愉快的数字。 </p><p>实现一个函数,如果数字是满意的,则返回true,否则返回false。 </p>
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# --hints--
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`happy`是一种功能。
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```js
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assert(typeof happy === 'function');
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```
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`happy(1)`应该返回一个布尔值。
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```js
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assert(typeof happy(1) === 'boolean');
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```
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`happy(1)`应该回归真实。
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```js
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assert(happy(1));
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```
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`happy(2)`应该返回虚假。
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```js
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assert(!happy(2));
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```
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`happy(7)`应该回归真实。
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```js
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assert(happy(7));
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```
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`happy(10)`应该回归真实。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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```js
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assert(happy(10));
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```
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`happy(13)`应该回归真实。
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```js
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assert(happy(13));
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2018-10-10 18:03:03 -04:00
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```
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2020-12-16 00:37:30 -07:00
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`happy(19)`应该回归真实。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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```js
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assert(happy(19));
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```
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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`happy(23)`应该回归真实。
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert(happy(23));
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```
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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`happy(28)`应该回归真实。
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```js
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assert(happy(28));
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2018-10-10 18:03:03 -04:00
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```
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2020-12-16 00:37:30 -07:00
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`happy(31)`应该回归真实。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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```js
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assert(happy(31));
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```
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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`happy(32)`应该回归真实:
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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```js
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assert(happy(32));
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```
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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`happy(33)`应该返回虚假。
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert(!happy(33));
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2018-10-10 18:03:03 -04:00
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```
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2020-08-13 17:24:35 +02:00
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2021-01-13 03:31:00 +01:00
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# --seed--
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## --seed-contents--
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```js
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function happy(number) {
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}
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```
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2020-12-16 00:37:30 -07:00
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# --solutions--
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2021-01-13 03:31:00 +01:00
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```js
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function happy (number) {
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let m;
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let digit;
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const cycle = [];
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while (number !== 1 && cycle[number] !== true) {
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cycle[number] = true;
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m = 0;
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while (number > 0) {
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digit = number % 10;
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m += Math.pow(digit, 2);
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number = (number - digit) / 10;
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}
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number = m;
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}
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return (number === 1);
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}
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```
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