2018-10-10 18:03:03 -04:00
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---
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id: af7588ade1100bde429baf20
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2021-01-12 08:18:51 -08:00
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title: 寻找缺失的字母
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2020-12-16 00:37:30 -07:00
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challengeType: 5
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2018-10-10 18:03:03 -04:00
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---
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2020-12-16 00:37:30 -07:00
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# --description--
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2021-01-12 08:18:51 -08:00
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在这道题目中,我们需要写一个函数,找出传入的字符串里缺失的字母并返回它。
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2018-10-10 18:03:03 -04:00
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2021-01-12 08:18:51 -08:00
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判断缺失的依据是字母顺序。对于没有缺失的情况,请返回 `undefined`。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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# --hints--
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2018-10-10 18:03:03 -04:00
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2021-01-12 08:18:51 -08:00
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`fearNotLetter("abce")` 应返回 "d"。
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert.deepEqual(fearNotLetter('abce'), 'd');
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2018-10-10 18:03:03 -04:00
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```
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2021-01-12 08:18:51 -08:00
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`fearNotLetter("abcdefghjklmno")` 应返回 "i"。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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```js
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assert.deepEqual(fearNotLetter('abcdefghjklmno'), 'i');
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```
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2018-10-10 18:03:03 -04:00
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2021-01-12 08:18:51 -08:00
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`fearNotLetter("stvwx")` 应返回 "u"。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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```js
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assert.deepEqual(fearNotLetter('stvwx'), 'u');
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```
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2021-01-12 08:18:51 -08:00
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`fearNotLetter("bcdf")` 应返回 "e"。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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```js
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assert.deepEqual(fearNotLetter('bcdf'), 'e');
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```
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2018-10-10 18:03:03 -04:00
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2021-01-12 08:18:51 -08:00
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`fearNotLetter("abcdefghijklmnopqrstuvwxyz")` 应返回 undefined。
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2020-09-07 16:10:29 +08:00
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert.isUndefined(fearNotLetter('abcdefghijklmnopqrstuvwxyz'));
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2018-10-10 18:03:03 -04:00
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```
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2020-08-13 17:24:35 +02:00
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2020-12-16 00:37:30 -07:00
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# --solutions--
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