2018-10-10 18:03:03 -04:00
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---
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id: 587d7dae367417b2b2512b7b
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2020-12-16 00:37:30 -07:00
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title: 了解自己的属性
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2018-10-10 18:03:03 -04:00
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challengeType: 1
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2020-08-04 15:15:28 +08:00
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forumTopicId: 301326
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2018-10-10 18:03:03 -04:00
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---
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2020-12-16 00:37:30 -07:00
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# --description--
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请看下面的实例,`Bird`构造函数定义了两个属性:`name`和`numLegs`:
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2020-08-04 15:15:28 +08:00
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```js
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function Bird(name) {
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this.name = name;
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this.numLegs = 2;
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}
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let duck = new Bird("Donald");
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let canary = new Bird("Tweety");
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```
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2020-12-16 00:37:30 -07:00
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`name`和`numLegs`被叫做`自身`属性,因为他们是直接在实例对象上定义的。这就意味着`duck`和`canary`这两个对象分别拥有这些属性的独立副本。 事实上,`Bird`的这些实例都将拥有这些属性的独立副本。 以下的代码将`duck`里面所有的`自身`属性都存到一个叫`ownProps`的数组里面:
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2020-08-04 15:15:28 +08:00
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```js
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let ownProps = [];
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for (let property in duck) {
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if(duck.hasOwnProperty(property)) {
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ownProps.push(property);
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}
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}
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console.log(ownProps); // prints [ "name", "numLegs" ]
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```
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2020-12-16 00:37:30 -07:00
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# --instructions--
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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将`canary`对象里面的`自身`属性添加到`ownProps`数组里面。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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# --hints--
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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`ownProps`应该包含`'numLegs'`和`'name'`两个属性的值。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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```js
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assert(ownProps.indexOf('name') !== -1 && ownProps.indexOf('numLegs') !== -1);
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2018-10-10 18:03:03 -04:00
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```
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2020-12-16 00:37:30 -07:00
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在不使用内置方法`Object.keys()`的情况下完成这个挑战。
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert(!/Object(\.keys|\[(['"`])keys\2\])/.test(code));
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2018-10-10 18:03:03 -04:00
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```
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2020-12-16 00:37:30 -07:00
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You should solve this challenge without hardcoding the `ownProps` array.
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2020-08-04 15:15:28 +08:00
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert(
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!/\[\s*(?:'|")(?:name|numLegs)|(?:push|concat)\(\s*(?:'|")(?:name|numLegs)/.test(
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code
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)
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);
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2018-10-10 18:03:03 -04:00
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```
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2020-08-04 15:15:28 +08:00
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2020-12-16 00:37:30 -07:00
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# --solutions--
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