2018-10-10 18:03:03 -04:00
|
|
|
|
---
|
|
|
|
|
id: 5900f3f21000cf542c50ff04
|
|
|
|
|
challengeType: 5
|
|
|
|
|
videoUrl: ''
|
2020-10-01 17:54:21 +02:00
|
|
|
|
title: 问题133:重新计算非因素
|
2018-10-10 18:03:03 -04:00
|
|
|
|
---
|
|
|
|
|
|
|
|
|
|
## Description
|
|
|
|
|
<section id="description">完全由1组成的数字称为repunit。我们将R(k)定义为长度k的重新定位;例如,R(6)= 111111.让我们考虑R(10n)形式的重新组合。虽然R(10),R(100)或R(1000)不能被17整除,但R(10000)可被17整除。但是没有n的值,R(10n)将除以19。事实上,值得注意的是,11,17,41和73是低于100的唯一四个素数,可以是R(10n)的因子。求出十万以下所有素数的总和,这些素数永远不会是R(10n)的因子。 </section>
|
|
|
|
|
|
|
|
|
|
## Instructions
|
|
|
|
|
<section id="instructions">
|
|
|
|
|
</section>
|
|
|
|
|
|
|
|
|
|
## Tests
|
|
|
|
|
<section id='tests'>
|
|
|
|
|
|
|
|
|
|
```yml
|
|
|
|
|
tests:
|
|
|
|
|
- text: <code>euler133()</code>应返回453647705。
|
2020-02-18 01:40:55 +09:00
|
|
|
|
testString: assert.strictEqual(euler133(), 453647705);
|
2018-10-10 18:03:03 -04:00
|
|
|
|
|
|
|
|
|
```
|
|
|
|
|
|
|
|
|
|
</section>
|
|
|
|
|
|
|
|
|
|
## Challenge Seed
|
|
|
|
|
<section id='challengeSeed'>
|
|
|
|
|
|
|
|
|
|
<div id='js-seed'>
|
|
|
|
|
|
|
|
|
|
```js
|
|
|
|
|
function euler133() {
|
|
|
|
|
// Good luck!
|
|
|
|
|
return true;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
euler133();
|
|
|
|
|
|
|
|
|
|
```
|
|
|
|
|
|
|
|
|
|
</div>
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
</section>
|
|
|
|
|
|
|
|
|
|
## Solution
|
|
|
|
|
<section id='solution'>
|
|
|
|
|
|
|
|
|
|
```js
|
|
|
|
|
// solution required
|
|
|
|
|
```
|
2020-08-13 17:24:35 +02:00
|
|
|
|
|
|
|
|
|
/section>
|