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							|  |  |  | id: 5900f49d1000cf542c50ffb0 | 
					
						
							|  |  |  | title: 'Problem 305: Reflexive Position' | 
					
						
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										 |  |  | challengeType: 5 | 
					
						
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										 |  |  | forumTopicId: 301959 | 
					
						
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										 |  |  | dashedName: problem-305-reflexive-position | 
					
						
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										 |  |  | # --description--
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										 |  |  | Let's call S the (infinite) string that is made by concatenating the consecutive positive integers (starting from 1) written down in base 10. | 
					
						
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										 |  |  | Thus, S = 1234567891011121314151617181920212223242... | 
					
						
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										 |  |  | It's easy to see that any number will show up an infinite number of times in S. | 
					
						
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										 |  |  | Let's call f(n) the starting position of the nth occurrence of n in S. For example, f(1)=1, f(5)=81, f(12)=271 and f(7780)=111111365. | 
					
						
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							|  |  |  | Find ∑f(3k) for 1≤k≤13. | 
					
						
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										 |  |  | # --hints--
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										 |  |  | `euler305()` should return 18174995535140. | 
					
						
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										 |  |  | ```js | 
					
						
							|  |  |  | assert.strictEqual(euler305(), 18174995535140); | 
					
						
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										 |  |  | ``` | 
					
						
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										 |  |  | # --seed--
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										 |  |  | ## --seed-contents--
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							|  |  |  | ```js | 
					
						
							|  |  |  | function euler305() { | 
					
						
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										 |  |  |   return true; | 
					
						
							|  |  |  | } | 
					
						
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							|  |  |  | euler305(); | 
					
						
							|  |  |  | ``` | 
					
						
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										 |  |  | # --solutions--
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							|  |  |  | ```js | 
					
						
							|  |  |  | // solution required | 
					
						
							|  |  |  | ``` |