2018-10-10 18:03:03 -04:00
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---
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id: ab306dbdcc907c7ddfc30830
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2021-01-12 08:18:51 -08:00
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title: 数组扁平化
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2018-10-10 18:03:03 -04:00
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challengeType: 5
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2020-09-07 16:10:29 +08:00
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forumTopicId: 16079
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2021-01-13 03:31:00 +01:00
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dashedName: steamroller
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2018-10-10 18:03:03 -04:00
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---
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2020-12-16 00:37:30 -07:00
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# --description--
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2018-10-10 18:03:03 -04:00
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2021-01-12 08:18:51 -08:00
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在这道题目中,我们需要写一个数组扁平化的函数。请注意考虑多层数组嵌套的情景。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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# --hints--
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2018-10-10 18:03:03 -04:00
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2021-01-12 08:18:51 -08:00
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`steamrollArray([[["a"]], [["b"]]])` 应返回 `["a", "b"]`。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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```js
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assert.deepEqual(steamrollArray([[['a']], [['b']]]), ['a', 'b']);
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2018-10-10 18:03:03 -04:00
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```
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2021-01-12 08:18:51 -08:00
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`steamrollArray([1, [2], [3, [[4]]]])` 应返回 `[1, 2, 3, 4]`。
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert.deepEqual(steamrollArray([1, [2], [3, [[4]]]]), [1, 2, 3, 4]);
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2018-10-10 18:03:03 -04:00
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```
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2021-01-12 08:18:51 -08:00
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`steamrollArray([1, [], [3, [[4]]]])` 应返回 `[1, 3, 4]`。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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```js
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assert.deepEqual(steamrollArray([1, [], [3, [[4]]]]), [1, 3, 4]);
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```
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2018-10-10 18:03:03 -04:00
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2021-01-12 08:18:51 -08:00
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`steamrollArray([1, {}, [3, [[4]]]])` 应返回 `[1, {}, 3, 4]`。
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2020-09-07 16:10:29 +08:00
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert.deepEqual(steamrollArray([1, {}, [3, [[4]]]]), [1, {}, 3, 4]);
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2018-10-10 18:03:03 -04:00
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```
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2020-08-13 17:24:35 +02:00
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2021-01-12 08:18:51 -08:00
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代码中不应使用 `Array.prototype.flat()` 或 `Array.prototype.flatMap()` 方法。
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```js
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assert(!code.match(/\.\s*flat\s*\(/) && !code.match(/\.\s*flatMap\s*\(/));
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```
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2021-01-13 03:31:00 +01:00
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# --seed--
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## --seed-contents--
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```js
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function steamrollArray(arr) {
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return arr;
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}
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steamrollArray([1, [2], [3, [[4]]]]);
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```
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2020-12-16 00:37:30 -07:00
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# --solutions--
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2021-01-13 03:31:00 +01:00
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```js
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function steamrollArray(arr) {
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if (!Array.isArray(arr)) {
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return [arr];
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}
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var out = [];
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arr.forEach(function(e) {
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steamrollArray(e).forEach(function(v) {
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out.push(v);
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});
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});
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return out;
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}
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```
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