2018-10-10 18:03:03 -04:00
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---
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id: 587d7dbb367417b2b2512bac
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2020-12-16 00:37:30 -07:00
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title: 删除开头和结尾的空白
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2018-10-10 18:03:03 -04:00
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challengeType: 1
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2020-08-04 15:14:01 +08:00
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forumTopicId: 301362
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2021-01-13 03:31:00 +01:00
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dashedName: remove-whitespace-from-start-and-end
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2018-10-10 18:03:03 -04:00
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---
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2020-12-16 00:37:30 -07:00
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# --description--
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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有时字符串周围存在的空白字符并不是必需的。字符串的典型处理是删除字符串开头和结尾处的空格。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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# --instructions--
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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编写一个正则表达式并使用适当的字符串方法删除字符串开头和结尾的空格。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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**注意:**
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`.trim()`方法在这里也可以实现同样的效果,但是你需要使用正则表达式来完成此项挑战。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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# --hints--
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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`结果`应该等于`'Hello, World!'`。
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert(result == 'Hello, World!');
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2018-10-10 18:03:03 -04:00
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```
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2020-12-16 00:37:30 -07:00
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你不应该使用`.trim()`方法。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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```js
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assert(!code.match(/\.trim\(.*?\)/));
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```
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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`结果`变量不应该设置为等于字符串。
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert(!code.match(/result\s*=\s*".*?"/));
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2018-10-10 18:03:03 -04:00
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```
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2020-08-04 15:14:01 +08:00
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2021-01-13 03:31:00 +01:00
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# --seed--
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## --seed-contents--
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```js
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let hello = " Hello, World! ";
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let wsRegex = /change/; // Change this line
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let result = hello; // Change this line
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```
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2020-12-16 00:37:30 -07:00
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# --solutions--
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2021-01-13 03:31:00 +01:00
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```js
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let hello = " Hello, World! ";
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let wsRegex = /^(\s+)(.+[^\s])(\s+)$/;
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let result = hello.replace(wsRegex, '$2');
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```
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