2018-10-10 18:03:03 -04:00
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---
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id: 587d8254367417b2b2512c71
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2020-12-16 00:37:30 -07:00
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title: 从ES6中的集中删除项目
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2018-10-10 18:03:03 -04:00
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challengeType: 1
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videoUrl: ''
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2021-01-13 03:31:00 +01:00
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dashedName: remove-items-from-a-set-in-es6
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2018-10-10 18:03:03 -04:00
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---
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2020-12-16 00:37:30 -07:00
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# --description--
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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让我们使用`delete`方法练习从ES6集中`delete` 。首先,创建一个ES6 Set `var set = new Set([1,2,3]);`现在使用`delete`方法从Set中删除一个项目。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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> set.delete(1);
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> console.log(\[... set])//应该返回\[2,3]
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>
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> >
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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# --instructions--
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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现在,创建一个整数为1,2,3,4和5的集合。删除值2和5,然后返回集合。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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# --hints--
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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您的集应包含值1,3和4
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert(
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(function () {
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var test = checkSet();
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return test.has(1) && test.has(3) && test.has(4) && test.size === 3;
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})()
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);
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2018-10-10 18:03:03 -04:00
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```
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2021-01-13 03:31:00 +01:00
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# --seed--
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## --seed-contents--
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```js
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function checkSet(){
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var set = null;
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return set;
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}
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```
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2020-12-16 00:37:30 -07:00
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# --solutions--
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2020-08-13 17:24:35 +02:00
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2021-01-13 03:31:00 +01:00
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```js
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function checkSet(){
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var set = new Set([1,2,3,4,5]);
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set.delete(2);
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set.delete(5);
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return set;}
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```
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