2018-10-10 18:03:03 -04:00
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---
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id: 5900f36e1000cf542c50fe80
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2020-12-16 00:37:30 -07:00
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title: 问题1:3和5的倍数
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2018-10-10 18:03:03 -04:00
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challengeType: 5
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videoUrl: ''
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2021-01-13 03:31:00 +01:00
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dashedName: problem-1-multiples-of-3-and-5
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2018-10-10 18:03:03 -04:00
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---
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2020-12-16 00:37:30 -07:00
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# --description--
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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如果我们列出所有10以下是3或5的倍数的自然数,我们会得到3,5,6和9。这些倍数的总和是23。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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求出所有在`number`以下的3或5的倍数的总和。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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# --hints--
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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`multiplesOf3and5(1000)`应该返回233168。
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert.strictEqual(multiplesOf3and5(1000), 233168);
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2018-10-10 18:03:03 -04:00
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```
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2020-12-16 00:37:30 -07:00
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`multiplesOf3and5(49)`应该返回543。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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```js
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assert.strictEqual(multiplesOf3and5(49), 543);
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```
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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`multiplesOf3and5(19564)`应该返回89301183。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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```js
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assert.strictEqual(multiplesOf3and5(19564), 89301183);
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```
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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您的函数未使用我们的测试值返回正确的结果。
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert.strictEqual(multiplesOf3and5(8456), 16687353);
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2018-10-10 18:03:03 -04:00
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```
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2020-08-13 17:24:35 +02:00
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2021-01-13 03:31:00 +01:00
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# --seed--
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## --seed-contents--
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```js
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function multiplesOf3and5(number) {
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return true;
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}
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multiplesOf3and5(1000);
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```
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2020-12-16 00:37:30 -07:00
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# --solutions--
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2021-01-13 03:31:00 +01:00
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```js
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const multiplesOf3and5 = (number) => {
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var total = 0;
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for(var i = 0; i < number; i++) {
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if(i % 3 == 0 || i % 5 == 0) {
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total += i;
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}
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}
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return total;
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};
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```
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