2018-10-10 18:03:03 -04:00
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---
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id: 5900f36f1000cf542c50fe82
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2020-12-16 00:37:30 -07:00
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title: 问题3:最大素数
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2018-10-10 18:03:03 -04:00
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challengeType: 5
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videoUrl: ''
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2021-01-13 03:31:00 +01:00
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dashedName: problem-3-largest-prime-factor
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2018-10-10 18:03:03 -04:00
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---
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2020-12-16 00:37:30 -07:00
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# --description--
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2020-02-18 01:40:55 +09:00
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13195的主要因子是5、7、13和29。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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给定<code>数字<!-- code-->的最大素数是多少?</code>
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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# --hints--
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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`largestPrimeFactor(2)`应该返回2。
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```js
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assert.strictEqual(largestPrimeFactor(2), 2);
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```
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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`largestPrimeFactor(3)`应该返回3。
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert.strictEqual(largestPrimeFactor(3), 3);
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```
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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`largestPrimeFactor(5)`应该返回5。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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```js
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assert.strictEqual(largestPrimeFactor(5), 5);
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2018-10-10 18:03:03 -04:00
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```
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2020-12-16 00:37:30 -07:00
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`largestPrimeFactor(7)`应该返回7。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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```js
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assert.strictEqual(largestPrimeFactor(7), 7);
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```
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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`largestPrimeFactor(13195)`应该返回29。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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```js
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assert.strictEqual(largestPrimeFactor(13195), 29);
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```
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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`largestPrimeFactor(600851475143)`应该返回6857。
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert.strictEqual(largestPrimeFactor(600851475143), 6857);
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2018-10-10 18:03:03 -04:00
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```
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2020-08-13 17:24:35 +02:00
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2021-01-13 03:31:00 +01:00
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# --seed--
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## --seed-contents--
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```js
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function largestPrimeFactor(number) {
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return true;
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}
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largestPrimeFactor(13195);
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```
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2020-12-16 00:37:30 -07:00
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# --solutions--
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2021-01-13 03:31:00 +01:00
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```js
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const largestPrimeFactor = (number) => {
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let largestFactor = number;
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for (let i = 2; i <= Math.sqrt(largestFactor); i++) {
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if (!(largestFactor % i)) {
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let factor = largestFactor / i;
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let candidate = largestPrimeFactor(factor);
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return i > candidate ? i : candidate;
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}
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}
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return largestFactor;
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}
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```
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