2018-10-10 18:03:03 -04:00
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---
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id: 5900f5081000cf542c51001a
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2020-12-16 00:37:30 -07:00
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title: 问题412:Gnomon编号
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2018-10-10 18:03:03 -04:00
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challengeType: 5
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videoUrl: ''
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2021-01-13 03:31:00 +01:00
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dashedName: problem-412-gnomon-numbering
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2018-10-10 18:03:03 -04:00
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---
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2020-12-16 00:37:30 -07:00
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# --description--
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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对于整数m,n(0≤n<m),令L(m,n)为m×m网格,其中右上n×n网格被移除。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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例如,L(5,3)看起来像这样:
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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我们希望用连续的整数1,2,3 ......对L(m,n)的每个单元进行编号,使得每个单元格中的数字小于它下面和左边的数字。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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例如,这里有两个有效的L(5,3)编号:
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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设LC(m,n)为L(m,n)的有效编号。可以证实LC(3,0)= 42,LC(5,3)= 250250,LC(6,3)= 406029023400和LC(10,5)mod 76543217 = 61251715。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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找到LC(10000,5000)mod 76543217。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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# --hints--
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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`euler412()`应该返回38788800。
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert.strictEqual(euler412(), 38788800);
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2018-10-10 18:03:03 -04:00
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```
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2020-08-13 17:24:35 +02:00
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2021-01-13 03:31:00 +01:00
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# --seed--
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## --seed-contents--
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```js
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function euler412() {
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return true;
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}
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euler412();
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```
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2020-12-16 00:37:30 -07:00
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# --solutions--
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2021-01-13 03:31:00 +01:00
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```js
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// solution required
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```
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