2018-10-10 18:03:03 -04:00
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---
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id: 5900f5271000cf542c51003a
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2020-12-16 00:37:30 -07:00
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title: 问题443:GCD序列
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2018-10-10 18:03:03 -04:00
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challengeType: 5
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videoUrl: ''
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2021-01-13 03:31:00 +01:00
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dashedName: problem-443-gcd-sequence
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2018-10-10 18:03:03 -04:00
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---
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2020-12-16 00:37:30 -07:00
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# --description--
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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设g(n)为如下定义的序列:g(4)= 13,g(n)= g(n-1)+ gcd(n,g(n-1)),n> 4。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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前几个值是:
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2018-10-10 18:03:03 -04:00
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```
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2020-12-16 00:37:30 -07:00
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n4567891011121314151617181920... g(n)1314161718272829303132333451545560...
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2018-10-10 18:03:03 -04:00
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```
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2020-12-16 00:37:30 -07:00
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给出g(1 000)= 2524和g(1 000 000)= 2624152。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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找到g(1015)。
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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# --hints--
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2018-10-10 18:03:03 -04:00
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2020-12-16 00:37:30 -07:00
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`euler443()`应该返回2744233049300770。
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2018-10-10 18:03:03 -04:00
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```js
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2020-12-16 00:37:30 -07:00
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assert.strictEqual(euler443(), 2744233049300770);
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2018-10-10 18:03:03 -04:00
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```
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2020-08-13 17:24:35 +02:00
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2021-01-13 03:31:00 +01:00
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# --seed--
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## --seed-contents--
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```js
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function euler443() {
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return true;
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}
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euler443();
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```
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2020-12-16 00:37:30 -07:00
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# --solutions--
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2021-01-13 03:31:00 +01:00
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```js
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// solution required
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```
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