freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/rosetta-code/i-before-e-except-after-c.md

---
id: 5a23c84252665b21eecc7eb0
title: I before E except after C
challengeType: 5
forumTopicId: 302288
dashedName: i-before-e-except-after-c
---

# --description--

The phrase ["I before E, except after C"](https://en.wikipedia.org/wiki/I before E except after C) is a widely known mnemonic which is supposed to help when spelling English words.

Using the words provided, check if the two sub-clauses of the phrase are plausible individually:

<ol>
  <li>
    <i>"I before E when not preceded by C".</i>
  </li>
  <li>
    <i>"E before I when preceded by C".</i>
  </li>
</ol>

If both sub-phrases are plausible then the original phrase can be said to be plausible.

# --instructions--

Write a function that accepts a word and check if the word follows this rule. The function should return true if the word follows the rule and false if it does not.

# --hints--

`IBeforeExceptC` should be a function.

```js
assert(typeof IBeforeExceptC == 'function');
```

`IBeforeExceptC("receive")` should return a boolean.

```js
assert(typeof IBeforeExceptC('receive') == 'boolean');
```

`IBeforeExceptC("receive")` should return `true`.

```js
assert.equal(IBeforeExceptC('receive'), true);
```

`IBeforeExceptC("science")` should return `false`.

```js
assert.equal(IBeforeExceptC('science'), false);
```

`IBeforeExceptC("imperceivable")` should return `true`.

```js
assert.equal(IBeforeExceptC('imperceivable'), true);
```

`IBeforeExceptC("inconceivable")` should return `true`.

```js
assert.equal(IBeforeExceptC('inconceivable'), true);
```

`IBeforeExceptC("insufficient")` should return `false`.

```js
assert.equal(IBeforeExceptC('insufficient'), false);
```

`IBeforeExceptC("omniscient")` should return `false`.

```js
assert.equal(IBeforeExceptC('omniscient'), false);
```

# --seed--

## --seed-contents--

```js
function IBeforeExceptC(word) {

}
```

# --solutions--

```js
function IBeforeExceptC(word)
{
    if(word.indexOf("c")==-1 && word.indexOf("ie")!=-1)
        return true;
    else if(word.indexOf("cei")!=-1)
        return true;
    return false;
}
```