freeCodeCamp/curriculum/challenges/english/02-javascript-algorithms-and-data-structures/basic-javascript/compound-assignment-with-augmented-division.md

---
id: 56533eb9ac21ba0edf2244b2
title: Compound Assignment With Augmented Division
challengeType: 1
videoUrl: 'https://scrimba.com/c/c2QvKT2'
forumTopicId: 16659
---

# --description--

The `/=` operator divides a variable by another number.

`myVar = myVar / 5;`

Will divide `myVar` by `5`. This can be rewritten as:

`myVar /= 5;`

# --instructions--

Convert the assignments for `a`, `b`, and `c` to use the `/=` operator.

# --hints--

`a` should equal `4`.

```js
assert(a === 4);
```

`b` should equal `27`.

```js
assert(b === 27);
```

`c` should equal `3`.

```js
assert(c === 3);
```

You should use the `/=` operator for each variable.

```js
assert(code.match(/\/=/g).length === 3);
```

You should not modify the code above the specified comment.

```js
assert(
  /var a = 48;/.test(code) &&
    /var b = 108;/.test(code) &&
    /var c = 33;/.test(code)
);
```

# --seed--

## --after-user-code--

```js
(function(a,b,c){ return "a = " + a + ", b = " + b + ", c = " + c; })(a,b,c);
```

## --seed-contents--

```js
var a = 48;
var b = 108;
var c = 33;

// Only change code below this line
a = a / 12;
b = b / 4;
c = c / 11;
```

# --solutions--

```js
var a = 48;
var b = 108;
var c = 33;

a /= 12;
b /= 4;
c /= 11;
```