88 lines
2.1 KiB
Markdown
88 lines
2.1 KiB
Markdown
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---
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id: a3bfc1673c0526e06d3ac698
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title: Sum All Primes
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isRequired: true
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challengeType: 5
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---
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## Description
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<section id='description'>
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Sum all the prime numbers up to and including the provided number.
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A prime number is defined as a number greater than one and having only two divisors, one and itself. For example, 2 is a prime number because it's only divisible by one and two.
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The provided number may not be a prime.
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Remember to use <a href='http://forum.freecodecamp.org/t/how-to-get-help-when-you-are-stuck/19514' target='_blank'>Read-Search-Ask</a> if you get stuck. Try to pair program. Write your own code.
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</section>
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## Instructions
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<section id='instructions'>
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</section>
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## Tests
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<section id='tests'>
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```yml
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- text: <code>sumPrimes(10)</code> should return a number.
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testString: 'assert.deepEqual(typeof sumPrimes(10), "number", "<code>sumPrimes(10)</code> should return a number.");'
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- text: <code>sumPrimes(10)</code> should return 17.
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testString: 'assert.deepEqual(sumPrimes(10), 17, "<code>sumPrimes(10)</code> should return 17.");'
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- text: <code>sumPrimes(977)</code> should return 73156.
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testString: 'assert.deepEqual(sumPrimes(977), 73156, "<code>sumPrimes(977)</code> should return 73156.");'
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```
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</section>
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## Challenge Seed
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<section id='challengeSeed'>
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<div id='js-seed'>
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```js
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function sumPrimes(num) {
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return num;
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}
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sumPrimes(10);
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```
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</div>
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</section>
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## Solution
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<section id='solution'>
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```js
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function eratosthenesArray(n) {
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var primes = [];
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if (n > 2) {
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var half = n>>1;
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var sieve = Array(half);
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for (var i = 1, limit = Math.sqrt(n)>>1; i <= limit; i++) {
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if (!sieve[i]) {
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for (var step = 2*i+1, j = (step*step)>>1; j < half; j+=step) {
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sieve[j] = true;
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}
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}
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}
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primes.push(2);
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for (var p = 1; p < half; p++) {
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if (!sieve[p]) primes.push(2*p+1);
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}
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}
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return primes;
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}
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function sumPrimes(num) {
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return eratosthenesArray(num+1).reduce(function(a,b) {return a+b;}, 0);
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}
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sumPrimes(10);
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```
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</section>
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