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								id: 5900f3ad1000cf542c50fec0
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								title: 'Problem 65: Convergents of e'
							 
						 
					
						
							
								
									
										
										
										
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								challengeType: 5
							 
						 
					
						
							
								
									
										
										
										
											2019-08-05 09:17:33 -07:00 
										
									 
								 
							 
							
								
									
										 
									 
								
							 
							
								 
							 
							
							
								forumTopicId: 302177
							 
						 
					
						
							
								
									
										
										
										
											2021-01-13 03:31:00 +01:00 
										
									 
								 
							 
							
								
									
										 
									 
								
							 
							
								 
							 
							
							
								dashedName: problem-65-convergents-of-e
							 
						 
					
						
							
								
									
										
										
										
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								---
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								
							 
						 
					
						
							
								
									
										
										
										
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								# --description--
 
							 
						 
					
						
							
								
									
										
										
										
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								The square root of 2 can be written as an infinite continued fraction.
							 
						 
					
						
							
								
									
										
										
										
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								$\\sqrt{2} = 1 + \\dfrac{1}{2 + \\dfrac{1}{2 + \\dfrac{1}{2 + \\dfrac{1}{2 + ...}}}}$
							 
						 
					
						
							
								
									
										
										
										
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								The infinite continued fraction can be written, $\\sqrt{2} = \[1; (2)]$ indicates that 2 repeats *ad infinitum* . In a similar way, $\\sqrt{23} = \[4; (1, 3, 1, 8)]$. It turns out that the sequence of partial values of continued fractions for square roots provide the best rational approximations. Let us consider the convergents for $\\sqrt{2}$.
							 
						 
					
						
							
								
									
										
										
										
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								$1 + \\dfrac{1}{2} = \\dfrac{3}{2}\\\\ 1 + \\dfrac{1}{2 + \\dfrac{1}{2}} = \\dfrac{7}{5}\\\\ 1 + \\dfrac{1}{2 + \\dfrac{1}{2 + \\dfrac{1}{2}}} = \\dfrac{17}{12}\\\\ 1 + \\dfrac{1}{2 + \\dfrac{1}{2 + \\dfrac{1}{2 + \\dfrac{1}{2}}}} = \\dfrac{41}{29}$
							 
						 
					
						
							
								
									
										
										
										
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								Hence the sequence of the first ten convergents for $\\sqrt{2}$ are:
							 
						 
					
						
							
								
									
										
										
										
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								$1, \\dfrac{3}{2}, \\dfrac{7}{5}, \\dfrac{17}{12}, \\dfrac{41}{29}, \\dfrac{99}{70}, \\dfrac{239}{169}, \\dfrac{577}{408}, \\dfrac{1393}{985}, \\dfrac{3363}{2378}, ...$
							 
						 
					
						
							
								
									
										
										
										
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								What is most surprising is that the important mathematical constant, $e = \[2; 1, 2, 1, 1, 4, 1, 1, 6, 1, ... , 1, 2k, 1, ...]$. The first ten terms in the sequence of convergents for `e`  are:
							 
						 
					
						
							
								
									
										
										
										
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								$2, 3, \\dfrac{8}{3}, \\dfrac{11}{4}, \\dfrac{19}{7}, \\dfrac{87}{32}, \\dfrac{106}{39}, \\dfrac{193}{71}, \\dfrac{1264}{465}, \\dfrac{1457}{536}, ...$
							 
						 
					
						
							
								
									
										
										
										
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								The sum of digits in the numerator of the 10< sup > th< / sup >  convergent is $1 + 4 + 5 + 7 = 17$.
							 
						 
					
						
							
								
									
										
										
										
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								Find the sum of digits in the numerator of the 100< sup > th</ sup >  convergent of the continued fraction for `e` .
							 
						 
					
						
							
								
									
										
										
										
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								# --hints--
 
							 
						 
					
						
							
								
									
										
										
										
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								`convergentsOfE()`  should return a number.
							 
						 
					
						
							
								
									
										
										
										
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								```js
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								assert(typeof convergentsOfE() === 'number');
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								```
							 
						 
					
						
							
								
									
										
										
										
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								`convergentsOfE()`  should return 272.
							 
						 
					
						
							
								
									
										
										
										
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								```js
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								assert.strictEqual(convergentsOfE(), 272);
							 
						 
					
						
							
								
									
										
										
										
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								```
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								
							 
						 
					
						
							
								
									
										
										
										
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								# --seed--
 
							 
						 
					
						
							
								
									
										
										
										
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								## --seed-contents--
 
							 
						 
					
						
							
								
									
										
										
										
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								```js
							 
						 
					
						
							
								
									
										
										
										
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								function convergentsOfE() {
							 
						 
					
						
							
								
									
										
										
										
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								  return true;
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								}
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								
							 
						 
					
						
							
								
									
										
										
										
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								convergentsOfE();
							 
						 
					
						
							
								
									
										
										
										
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								```
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								
							 
						 
					
						
							
								
									
										
										
										
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								# --solutions--
 
							 
						 
					
						
							
								
									
										
										
										
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								```js
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								// solution required
							 
						 
					
						
							
								
							 
							
								
							 
							
								 
							 
							
							
								```