68 lines
1.2 KiB
Markdown
68 lines
1.2 KiB
Markdown
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---
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id: 56104e9e514f539506016a5c
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title: Iterate Odd Numbers With a For Loop
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challengeType: 1
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videoUrl: 'https://scrimba.com/c/cm8n7T9'
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forumTopicId: 18212
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dashedName: iterate-odd-numbers-with-a-for-loop
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---
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# --description--
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For loops don't have to iterate one at a time. By changing our `final-expression`, we can count by even numbers.
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We'll start at `i = 0` and loop while `i < 10`. We'll increment `i` by 2 each loop with `i += 2`.
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```js
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var ourArray = [];
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for (var i = 0; i < 10; i += 2) {
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ourArray.push(i);
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}
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```
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`ourArray` will now contain `[0,2,4,6,8]`. Let's change our `initialization` so we can count by odd numbers.
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# --instructions--
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Push the odd numbers from 1 through 9 to `myArray` using a `for` loop.
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# --hints--
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You should be using a `for` loop for this.
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```js
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assert(/for\s*\([^)]+?\)/.test(code));
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```
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`myArray` should equal `[1,3,5,7,9]`.
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```js
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assert.deepEqual(myArray, [1, 3, 5, 7, 9]);
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```
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# --seed--
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## --after-user-code--
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```js
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if(typeof myArray !== "undefined"){(function(){return myArray;})();}
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```
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## --seed-contents--
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```js
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// Setup
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var myArray = [];
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// Only change code below this line
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```
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# --solutions--
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```js
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var myArray = [];
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for (var i = 1; i < 10; i += 2) {
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myArray.push(i);
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}
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```
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