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								id: 5900f3891000cf542c50fe9c
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								title: 'Problem 29: Distinct powers'
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								challengeType: 5
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											2019-08-05 09:17:33 -07:00
										 
									 
								 
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								forumTopicId: 301941
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											2021-01-13 03:31:00 +01:00
										 
									 
								 
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								dashedName: problem-29-distinct-powers
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								---
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								# --description--
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											2020-02-28 21:39:47 +09:00
										 
									 
								 
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								Consider all integer combinations of ab for 2 ≤ a ≤ 5 and 2 ≤ b ≤ 5:
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								<div style='padding-left: 4em;'>
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								  2<sup>2</sup>=4, 2<sup>3</sup>=8, 2<sup>4</sup>=16, 2<sup>5</sup>=32 <br>
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								  3<sup>2</sup>=9, 3<sup>3</sup>=27, 3<sup>4</sup>=81, 3<sup>5</sup>=243 <br>
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								  4<sup>2</sup>=16, 4<sup>3</sup>=64, 4<sup>4</sup>=256, 4<sup>5</sup>=1024 <br>
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								  5<sup>2</sup>=25, 5<sup>3</sup>=125, 5<sup>4</sup>=625, 5<sup>5</sup>=3125 <br>
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								</div>
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								If they are then placed in numerical order, with any repeats removed, we get the following sequence of 15 distinct terms:
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								<div style='padding-left: 4em;'>
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								  4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125
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								</div>
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								How many distinct terms are in the sequence generated by `ab` for 2 ≤ `a` ≤ `n` and 2 ≤ `b` ≤ `n`?
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								# --hints--
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								`distinctPowers(15)` should return a number.
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								```js
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								assert(typeof distinctPowers(15) === 'number');
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								```
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								`distinctPowers(15)` should return 177.
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								```js
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								assert.strictEqual(distinctPowers(15), 177);
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								```
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								`distinctPowers(20)` should return 324.
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								```js
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								assert.strictEqual(distinctPowers(20), 324);
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								```
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								`distinctPowers(25)` should return 519.
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								```js
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								assert.strictEqual(distinctPowers(25), 519);
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								```
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											2020-09-15 09:57:40 -07:00
										 
									 
								 
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								`distinctPowers(30)` should return 755.
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								```js
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								assert.strictEqual(distinctPowers(30), 755);
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								```
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								# --seed--
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								## --seed-contents--
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								```js
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								function distinctPowers(n) {
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								  return n;
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								}
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								distinctPowers(30);
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								```
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								# --solutions--
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								```js
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								const distinctPowers = (n) => {
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								  let list = [];
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								  for (let a=2; a<=n; a++) {
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								    for (let b=2; b<=n; b++) {
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								      let term = Math.pow(a, b);
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								      if (list.indexOf(term)===-1) list.push(term);
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								    }
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								  }
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								  return list.length;
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								};
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								```
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