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							|  |  |  |  | id: 5900f3e71000cf542c50fefa | 
					
						
							|  |  |  |  | title: 'Problem 123: Prime square remainders' | 
					
						
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										 |  |  |  | challengeType: 5 | 
					
						
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										 |  |  |  | forumTopicId: 301750 | 
					
						
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										 |  |  |  | dashedName: problem-123-prime-square-remainders | 
					
						
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										 |  |  |  | # --description--
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										 |  |  |  | Let pn be the nth prime: 2, 3, 5, 7, 11, ..., and let r be the remainder when (pn−1)n + (pn+1)n is divided by pn2. | 
					
						
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										 |  |  |  | For example, when n = 3, p3 = 5, and 43 + 63 = 280 ≡ 5 mod 25. | 
					
						
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										 |  |  |  | The least value of n for which the remainder first exceeds 109 is 7037. | 
					
						
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										 |  |  |  | Find the least value of n for which the remainder first exceeds 1010. | 
					
						
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										 |  |  |  | # --hints--
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										 |  |  |  | `euler123()` should return 21035. | 
					
						
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										 |  |  |  | ```js | 
					
						
							|  |  |  |  | assert.strictEqual(euler123(), 21035); | 
					
						
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										 |  |  |  | ``` | 
					
						
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										 |  |  |  | # --seed--
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										 |  |  |  | ## --seed-contents--
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							|  |  |  |  | ```js | 
					
						
							|  |  |  |  | function euler123() { | 
					
						
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										 |  |  |  |   return true; | 
					
						
							|  |  |  |  | } | 
					
						
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							|  |  |  |  | euler123(); | 
					
						
							|  |  |  |  | ``` | 
					
						
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										 |  |  |  | # --solutions--
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							|  |  |  |  | ```js | 
					
						
							|  |  |  |  | // solution required | 
					
						
							|  |  |  |  | ``` |