85 lines
		
	
	
		
			3.0 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
		
		
			
		
	
	
			85 lines
		
	
	
		
			3.0 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
|   | --- | |||
|  | title: Freecodecamp Algorithm Bubble Sort Guide | |||
|  | localeTitle: Freecodecamp算法冒泡排序指南 | |||
|  | --- | |||
|  | 冒泡排序是一种简单的排序算法。该排序算法是基于比较的算法,其中每对相邻元素是   | |||
|  | 比较和元素交换,如果它们不合适。该算法进行就地排序,即它不会创建新数组   | |||
|  | 进行分拣过程。 | |||
|  | 
 | |||
|  | #### 例
 | |||
|  | 
 | |||
|  | [BubbleSort的动画](http://www.sorting-algorithms.com/bubble-sort) | |||
|  | ``` | |||
|  | array = <a href='https://repl.it/CXif' target='_blank' rel='nofollow'>5, 1, 4, 2, 8]  | |||
|  |   | |||
|  |  First Pass:  | |||
|  |  ( 5 1 4 2 8 ) –> ( 1 5 4 2 8 ), Here, algorithm compares the first two elements, and swaps since 5 > 1.  | |||
|  |  ( 1 5 4 2 8 ) –>  ( 1 4 5 2 8 ), Swap since 5 > 4  | |||
|  |  ( 1 4 5 2 8 ) –>  ( 1 4 2 5 8 ), Swap since 5 > 2  | |||
|  |  ( 1 4 2 5 8 ) –> ( 1 4 2 5 8 ), Now, since these elements are already in order (8 > 5), algorithm does not swap them.  | |||
|  |   | |||
|  |  Second Pass:  | |||
|  |  ( 1 4 2 5 8 ) –> ( 1 4 2 5 8 )  | |||
|  |  ( 1 4 2 5 8 ) –> ( 1 2 4 5 8 ), Swap since 4 > 2  | |||
|  |  ( 1 2 4 5 8 ) –> ( 1 2 4 5 8 )  | |||
|  |  ( 1 2 4 5 8 ) –>  ( 1 2 4 5 8 )  | |||
|  |  Now, the array is already sorted, but our algorithm does not know if it is completed. The algorithm needs one whole pass without any  | |||
|  |  swap to know it is sorted.  | |||
|  |   | |||
|  |  Third Pass:  | |||
|  |  ( 1 2 4 5 8 ) –> ( 1 2 4 5 8 )  | |||
|  |  ( 1 2 4 5 8 ) –> ( 1 2 4 5 8 )  | |||
|  |  ( 1 2 4 5 8 ) –> ( 1 2 4 5 8 )  | |||
|  |  ( 1 2 4 5 8 ) –> ( 1 2 4 5 8 )  | |||
|  | ``` | |||
|  | 
 | |||
|  | #### C ++实现
 | |||
|  | ``` | |||
|  | // Function to implement bubble sort  | |||
|  |  void bubble_sort(int array[], int n)  | |||
|  |  {  | |||
|  |     // Here n is the number of elements in array  | |||
|  |     int temp;  | |||
|  |   | |||
|  |     for(int i = 0; i < n-1; i++)  | |||
|  |  {  | |||
|  |     // Last i elements are already in place  | |||
|  |     for(int j = 0; j < ni-1; j++)  | |||
|  |     {  | |||
|  |         if (array[j] > array[j+1])  | |||
|  |         {  | |||
|  |             // swap elements at index j and j+1  | |||
|  |             temp = array[j];  | |||
|  |             array[j] = array[j+1];  | |||
|  |             array[j+1] = temp;  | |||
|  |         }  | |||
|  |     }  | |||
|  |  }  | |||
|  |  }  | |||
|  | ``` | |||
|  | 
 | |||
|  | :rocket:\[运行代码#### Python实现 | |||
|  | ``` | |||
|  | def bubble_sort(arr):  | |||
|  |     exchanges = True # A check to see if the array is already sorted so that no further steps gets executed  | |||
|  |     i = len(arr)-1  | |||
|  |     while i > 0 and exchanges:  | |||
|  |        exchanges = False  | |||
|  |        for j in range(i):  | |||
|  |            if arr<a href='https://forum.freecodecamp.com/images/emoji/emoji_one/rocket.png?v=3 ":rocket:"' target='_blank' rel='nofollow'>j]>arr[j+1]:  | |||
|  |                exchanges = True  | |||
|  |                arr[j], arr[j+1] = arr[j+1], arr[j]  | |||
|  |        i -= 1  | |||
|  |   | |||
|  |  arr = [5,3,23,1,43,2,54]  | |||
|  |  bubble_sort(arr)  | |||
|  |  print(arr) # Prints [1, 2, 3, 5, 23, 43, 54]  | |||
|  | ``` | |||
|  | 
 | |||
|  |  [运行代码](https://repl.it/CW0M/1) | |||
|  | 
 | |||
|  | #### [算法的复杂性](https://www.freecodecamp.com/videos/big-o-notation-what-it-is-and-why-you-should-care)
 | |||
|  | 
 | |||
|  | **最差和平均案例时间复杂度:** O(n \* n)。当数组被反向排序时,即最坏的情况发生,即元素按递减顺序排列 | |||
|  | 
 | |||
|  | **最佳案例时间复杂度:** O(n)。当数组已经排序时,会出现最佳情况。 |