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										 |  |  | title: Count occurrences of a substring | 
					
						
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										 |  |  | challengeType: 5 | 
					
						
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										 |  |  | forumTopicId: 302237 | 
					
						
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											2021-01-13 03:31:00 +01:00
										 |  |  | dashedName: count-occurrences-of-a-substring | 
					
						
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										 |  |  | # --description--
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											2019-02-25 13:36:09 +09:00
										 |  |  | Create a function, or show a built-in function, to count the number of non-overlapping occurrences of a substring inside a string. | 
					
						
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										 |  |  | The function should take two arguments: | 
					
						
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										 |  |  | <ul> | 
					
						
							|  |  |  |   <li>the first argument being the string to search, and</li> | 
					
						
							|  |  |  |   <li>the second a substring to be searched for.</li> | 
					
						
							|  |  |  | </ul> | 
					
						
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										 |  |  | It should return an integer count. | 
					
						
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										 |  |  | The matching should yield the highest number of non-overlapping matches. | 
					
						
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										 |  |  | In general, this essentially means matching from left-to-right or right-to-left. | 
					
						
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										 |  |  | # --hints--
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										 |  |  | `countSubstring` should be a function. | 
					
						
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										 |  |  | ```js | 
					
						
							|  |  |  | assert(typeof countSubstring === 'function'); | 
					
						
							|  |  |  | ``` | 
					
						
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										 |  |  | `countSubstring("the three truths", "th")` should return `3`. | 
					
						
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										 |  |  | ```js | 
					
						
							|  |  |  | assert.equal(countSubstring(testCases[0], searchString[0]), results[0]); | 
					
						
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										 |  |  | ``` | 
					
						
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										 |  |  | `countSubstring("ababababab", "abab")` should return `2`. | 
					
						
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										 |  |  | ```js | 
					
						
							|  |  |  | assert.equal(countSubstring(testCases[1], searchString[1]), results[1]); | 
					
						
							|  |  |  | ``` | 
					
						
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										 |  |  | `countSubstring("abaabba*bbaba*bbab", "a*b")` should return `2`. | 
					
						
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							|  |  |  | ```js | 
					
						
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										 |  |  | assert.equal(countSubstring(testCases[2], searchString[2]), results[2]); | 
					
						
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										 |  |  | ``` | 
					
						
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										 |  |  | # --seed--
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										 |  |  | ## --after-user-code--
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							|  |  |  | ```js | 
					
						
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										 |  |  | const testCases = ['the three truths', 'ababababab', 'abaabba*bbaba*bbab']; | 
					
						
							|  |  |  | const searchString = ['th', 'abab', 'a*b']; | 
					
						
							|  |  |  | const results = [3, 2, 2]; | 
					
						
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										 |  |  | ``` | 
					
						
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										 |  |  | ## --seed-contents--
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										 |  |  | ```js | 
					
						
							|  |  |  | function countSubstring(str, subStr) { | 
					
						
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										 |  |  |   return true; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | ``` | 
					
						
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										 |  |  | # --solutions--
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							|  |  |  | ```js | 
					
						
							|  |  |  | function countSubstring(str, subStr) { | 
					
						
							|  |  |  |   const escapedSubStr = subStr.replace(/[.+*?^$[\]{}()|/]/g, '\\$&'); | 
					
						
							|  |  |  |   const matches = str.match(new RegExp(escapedSubStr, 'g')); | 
					
						
							|  |  |  |   return matches ? matches.length : 0; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | ``` |