55 lines
		
	
	
		
			1.3 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
		
		
			
		
	
	
			55 lines
		
	
	
		
			1.3 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
|   | --- | |||
|  | id: 5900f4231000cf542c50ff36 | |||
|  | title: 'Problem 183: Maximum product of parts' | |||
|  | challengeType: 5 | |||
|  | forumTopicId: 301819 | |||
|  | dashedName: problem-183-maximum-product-of-parts | |||
|  | --- | |||
|  | 
 | |||
|  | # --description--
 | |||
|  | 
 | |||
|  | Let N be a positive integer and let N be split into k equal parts, r = N/k, so that N = r + r + ... + r. | |||
|  | 
 | |||
|  | Let P be the product of these parts, P = r × r × ... × r = rk. | |||
|  | 
 | |||
|  | For example, if 11 is split into five equal parts, 11 = 2.2 + 2.2 + 2.2 + 2.2 + 2.2, then P = 2.25 = 51.53632. | |||
|  | 
 | |||
|  | Let M(N) = Pmax for a given value of N. | |||
|  | 
 | |||
|  | It turns out that the maximum for N = 11 is found by splitting eleven into four equal parts which leads to Pmax = (11/4)4; that is, M(11) = 14641/256 = 57.19140625, which is a terminating decimal. | |||
|  | 
 | |||
|  | However, for N = 8 the maximum is achieved by splitting it into three equal parts, so M(8) = 512/27, which is a non-terminating decimal. | |||
|  | 
 | |||
|  | Let D(N) = N if M(N) is a non-terminating decimal and D(N) = -N if M(N) is a terminating decimal. | |||
|  | 
 | |||
|  | For example, ΣD(N) for 5 ≤ N ≤ 100 is 2438. | |||
|  | 
 | |||
|  | Find ΣD(N) for 5 ≤ N ≤ 10000. | |||
|  | 
 | |||
|  | # --hints--
 | |||
|  | 
 | |||
|  | `euler183()` should return 48861552. | |||
|  | 
 | |||
|  | ```js | |||
|  | assert.strictEqual(euler183(), 48861552); | |||
|  | ``` | |||
|  | 
 | |||
|  | # --seed--
 | |||
|  | 
 | |||
|  | ## --seed-contents--
 | |||
|  | 
 | |||
|  | ```js | |||
|  | function euler183() { | |||
|  | 
 | |||
|  |   return true; | |||
|  | } | |||
|  | 
 | |||
|  | euler183(); | |||
|  | ``` | |||
|  | 
 | |||
|  | # --solutions--
 | |||
|  | 
 | |||
|  | ```js | |||
|  | // solution required | |||
|  | ``` |