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								id: 5900f3a01000cf542c50feb3
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								title: 'Problem 52: Permuted multiples'
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								challengeType: 5
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								forumTopicId: 302163
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								dashedName: problem-52-permuted-multiples
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								---
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								# --description--
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								It can be seen that the number, 125874, and its double, 251748, contain exactly the same digits, but in a different order.
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								Find the smallest positive integer, such that multiplied by integers $\\{2, 3, \ldots, n\\}$, contain the same digits.
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								# --hints--
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								`permutedMultiples(2)` should return a number.
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								```js
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								assert(typeof permutedMultiples(2) === 'number');
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								```
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								`permutedMultiples(2)` should return `125874`.
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								```js
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								assert.strictEqual(permutedMultiples(2), 125874);
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								```
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								`permutedMultiples(6)` should return `142857`.
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								```js
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								assert.strictEqual(permutedMultiples(6), 142857);
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								```
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								# --seed--
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								## --seed-contents--
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								```js
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								function permutedMultiples(n) {
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								  return true;
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								}
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								permutedMultiples(2);
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								```
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								# --solutions--
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								```js
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								function permutedMultiples(n) {
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								    const isPermutation = (a, b) =>
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								        a.length !== b.length
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								            ? false
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								            : a.split('').sort().join() === b.split('').sort().join();
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								    let start = 1;
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								    let found = false;
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								    let result = 0;
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								    while (!found) {
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								        start *= 10;
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								        for (let i = start; i < start * 10 / n; i++) {
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								            found = true;
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								            for (let j = 2; j <= n; j++) {
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								                if (!isPermutation(i + '', j * i + '')) {
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								                    found = false;
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								                    break;
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								                }
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								            }
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								            if (found) {
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								                result = i;
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								                break;
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								            }
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								        }
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								    }
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								    return result;
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								}
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								```
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