125 lines
		
	
	
		
			2.9 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
		
		
			
		
	
	
			125 lines
		
	
	
		
			2.9 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
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								id: 594faaab4e2a8626833e9c3d
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								title: Tokenize a string with escaping
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								challengeType: 5
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								forumTopicId: 302338
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								dashedName: tokenize-a-string-with-escaping
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								---
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								# --description--
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								Write a function or program that can split a string at each non-escaped occurrence of a separator character.
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								It should accept three input parameters:
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								<ul>
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								  <li>The <strong>string</strong></li>
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								  <li>The <strong>separator character</strong></li>
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								  <li>The <strong>escape character</strong></li>
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								</ul>
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								It should output a list of strings.
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								Rules for splitting:
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								<ul>
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								  <li>The fields that were separated by the separators, become the elements of the output list.</li>
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								  <li>Empty fields should be preserved, even at the start and end.</li>
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								</ul>
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								Rules for escaping:
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								<ul>
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								  <li>"Escaped" means preceded by an occurrence of the escape character that is not already escaped itself.</li>
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								  <li>When the escape character precedes a character that has no special meaning, it still counts as an escape (but does not do anything special).</li>
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								  <li>Each occurrences of the escape character that was used to escape something, should not become part of the output.</li>
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								</ul>
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								Demonstrate that your function satisfies the following test-case:
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								Given the string
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								<pre>one^|uno||three^^^^|four^^^|^cuatro|</pre>
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								and using `|` as a separator and `^` as escape character, your function should output the following array:
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								<pre>  ['one|uno', '', 'three^^', 'four^|cuatro', '']
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								</pre>
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								# --hints--
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								`tokenize` should be a function.
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								```js
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								assert(typeof tokenize === 'function');
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								```
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								`tokenize` should return an array.
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								```js
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								assert(typeof tokenize('a', 'b', 'c') === 'object');
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								```
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								`tokenize('one^|uno||three^^^^|four^^^|^cuatro|', '|', '^')` should return `['one|uno', '', 'three^^', 'four^|cuatro', '']`
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								```js
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								assert.deepEqual(tokenize(testStr1, '|', '^'), res1);
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								```
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								`tokenize('a@&bcd&ef&&@@hi', '&', '@')` should return `['a&bcd', 'ef', '', '@hi']`
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								```js
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								assert.deepEqual(tokenize(testStr2, '&', '@'), res2);
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								```
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								# --seed--
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								## --after-user-code--
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								```js
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								const testStr1 = 'one^|uno||three^^^^|four^^^|^cuatro|';
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								const res1 = ['one|uno', '', 'three^^', 'four^|cuatro', ''];
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								// TODO add more tests
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								const testStr2 = 'a@&bcd&ef&&@@hi';
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								const res2 = ['a&bcd', 'ef', '', '@hi'];
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								```
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								## --seed-contents--
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								```js
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								function tokenize(str, sep, esc) {
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								  return true;
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								}
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								```
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								# --solutions--
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								```js
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								// tokenize :: String -> Character -> Character -> [String]
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								function tokenize(str, charDelim, charEsc) {
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								  const dctParse = str.split('')
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								    .reduce((a, x) => {
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								      const blnEsc = a.esc;
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								      const blnBreak = !blnEsc && x === charDelim;
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								      const blnEscChar = !blnEsc && x === charEsc;
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								      return {
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								        esc: blnEscChar,
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								        token: blnBreak ? '' : (
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								          a.token + (blnEscChar ? '' : x)
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								        ),
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								        list: a.list.concat(blnBreak ? a.token : [])
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								      };
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								    }, {
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								      esc: false,
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								      token: '',
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								      list: []
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								    });
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								  return dctParse.list.concat(
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								    dctParse.token
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								  );
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								}
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								```
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