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							|  |  |  | id: 5900f47b1000cf542c50ff8d | 
					
						
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										 |  |  | title: 'Problema 271: Cubos modulares, parte 1' | 
					
						
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										 |  |  | challengeType: 5 | 
					
						
							|  |  |  | forumTopicId: 301921 | 
					
						
							|  |  |  | dashedName: problem-271-modular-cubes-part-1 | 
					
						
							|  |  |  | --- | 
					
						
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							|  |  |  | # --description--
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										 |  |  | Para um número positivo $n$, defina $S(n)$ como a soma dos números inteiros $x$, para a qual $1 < x < n$ e $x^3 \equiv 1\bmod n$. | 
					
						
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										 |  |  | Quando $n = 91$, existem 8 valores possíveis $x$: 9, 16, 22, 29, 53, 74, 79 e 81. Portanto, $S(91) = 9 + 16 + 22 + 29 + 53 + 74 + 79 + 81 = 363$. | 
					
						
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										 |  |  | Encontre $S(13.082.761.331.670.030)$. | 
					
						
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							|  |  |  | # --hints--
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										 |  |  | `modularCubesOne()` deve retornar `4617456485273130000`. | 
					
						
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							|  |  |  | ```js | 
					
						
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										 |  |  | assert.strictEqual(modularCubesOne(), 4617456485273130000); | 
					
						
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										 |  |  | ``` | 
					
						
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							|  |  |  | # --seed--
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							|  |  |  | ## --seed-contents--
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							|  |  |  | ```js | 
					
						
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										 |  |  | function modularCubesOne() { | 
					
						
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							|  |  |  |   return true; | 
					
						
							|  |  |  | } | 
					
						
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										 |  |  | modularCubesOne(); | 
					
						
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										 |  |  | ``` | 
					
						
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							|  |  |  | # --solutions--
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							|  |  |  | ```js | 
					
						
							|  |  |  | // solution required | 
					
						
							|  |  |  | ``` |