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								id: 59713bd26bdeb8a594fb9413
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											2020-11-27 19:02:05 +01:00
										 
									 
								 
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								title: Count the coins
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								challengeType: 5
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											2019-08-05 09:17:33 -07:00
										 
									 
								 
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								forumTopicId: 302238
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											2021-01-13 03:31:00 +01:00
										 
									 
								 
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								dashedName: count-the-coins
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								---
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											2020-11-27 19:02:05 +01:00
										 
									 
								 
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								# --description--
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								There are four types of common coins in [US](https://en.wikipedia.org/wiki/United_States) currency:
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											2019-02-25 13:36:09 +09:00
										 
									 
								 
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								<ul>
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								  <li>quarters (25 cents)</li>
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								  <li>dimes (10 cents)</li>
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								  <li>nickels (5 cents), and</li>
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								  <li>pennies (1 cent)</li>
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								</ul>
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								<p>There are six ways to make change for 15 cents:</p>
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											2019-02-25 13:36:09 +09:00
										 
									 
								 
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								<ul>
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								  <li>A dime and a nickel</li>
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								  <li>A dime and 5 pennies</li>
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								  <li>3 nickels</li>
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								  <li>2 nickels and 5 pennies</li>
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								  <li>A nickel and 10 pennies</li>
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								  <li>15 pennies</li>
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								</ul>
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								# --instructions--
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											2019-03-01 17:10:50 +09:00
										 
									 
								 
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								Implement a function to determine how many ways there are to make change for a dollar using these common coins (1 dollar = 100 cents)
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								# --hints--
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								`countCoins` should be a function.
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								```js
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								assert(typeof countCoins === 'function');
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								```
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								`countCoins()` should return 242.
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								```js
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								assert.equal(countCoins(), 242);
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								```
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								# --seed--
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								## --seed-contents--
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								```js
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								function countCoins() {
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								  return true;
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								}
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								```
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								# --solutions--
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								```js
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								function countCoins() {
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								  let t = 100;
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								  const operands = [1, 5, 10, 25];
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								  const targetsLength = t + 1;
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								  const operandsLength = operands.length;
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								  t = [1];
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								  for (let a = 0; a < operandsLength; a++) {
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								    for (let b = 1; b < targetsLength; b++) {
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								      // initialise undefined target
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								      t[b] = t[b] ? t[b] : 0;
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								      // accumulate target + operand ways
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								      t[b] += (b < operands[a]) ? 0 : t[b - operands[a]];
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								    }
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								  }
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								  return t[targetsLength - 1];
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								}
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								```
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