chore(i18n,curriculum): update translations (#43881)
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id: a7bf700cd123b9a54eef01d5
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title: No Repeats Please
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title: 請不要重複
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challengeType: 5
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forumTopicId: 16037
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dashedName: no-repeats-please
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@ -8,67 +8,67 @@ dashedName: no-repeats-please
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# --description--
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Return the number of total permutations of the provided string that don't have repeated consecutive letters. Assume that all characters in the provided string are each unique.
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返回沒有重複連續字母的提供字符串的總排列數。 假設提供的字符串中的所有字符都是唯一的。
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For example, `aab` should return 2 because it has 6 total permutations (`aab`, `aab`, `aba`, `aba`, `baa`, `baa`), but only 2 of them (`aba` and `aba`) don't have the same letter (in this case `a`) repeating.
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例如,`aab` 應該返回 2,因爲它有 6 個排列(`aab`、`aab`、`aba`、`aba`、`baa` 和 `baa`),但其中只有 2 個(`aba` 和 `aba`)沒有重複相同字符(即 `a`)。
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# --hints--
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`permAlone("aab")` should return a number.
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`permAlone("aab")` 應返回 2。
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```js
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assert.isNumber(permAlone('aab'));
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```
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`permAlone("aab")` should return 2.
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`permAlone("aab")` 應該返回 2。
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```js
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assert.strictEqual(permAlone('aab'), 2);
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```
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`permAlone("aaa")` should return 0.
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`permAlone("aaa")` 應該返回 0。
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```js
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assert.strictEqual(permAlone('aaa'), 0);
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```
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`permAlone("aabb")` should return 8.
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`permAlone("aabb")`應返回 8。
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```js
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assert.strictEqual(permAlone('aabb'), 8);
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```
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`permAlone("abcdefa")` should return 3600.
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`permAlone("abcdefa")`應返回 3600。
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```js
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assert.strictEqual(permAlone('abcdefa'), 3600);
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```
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`permAlone("abfdefa")` should return 2640.
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`permAlone("abfdefa")`應該返回 2640。
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```js
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assert.strictEqual(permAlone('abfdefa'), 2640);
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```
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`permAlone("zzzzzzzz")` should return 0.
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`permAlone("zzzzzzzz")` 應返回 0。
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```js
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assert.strictEqual(permAlone('zzzzzzzz'), 0);
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```
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`permAlone("a")` should return 1.
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`permAlone("a")` 應該返回 1。
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```js
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assert.strictEqual(permAlone('a'), 1);
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```
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`permAlone("aaab")` should return 0.
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`permAlone("aaab")` 應該返回 0。
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```js
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assert.strictEqual(permAlone('aaab'), 0);
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```
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`permAlone("aaabb")` should return 12.
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`permAlone("aaabb")` 應返回 12.
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```js
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assert.strictEqual(permAlone('aaabb'), 12);
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