Feat: add new Markdown parser (#39800)

and change all the challenges to new `md` format.
This commit is contained in:
Oliver Eyton-Williams
2020-11-27 19:02:05 +01:00
committed by GitHub
parent a07f84c8ec
commit 0bd52f8bd1
2580 changed files with 113436 additions and 111979 deletions

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@ -1,12 +1,12 @@
---
id: 5900f4531000cf542c50ff65
challengeType: 5
title: 'Problem 230: Fibonacci Words'
challengeType: 5
forumTopicId: 301874
---
## Description
<section id='description'>
# --description--
For any two strings of digits, A and B, we define FA,B to be the sequence (A,B,AB,BAB,ABBAB,...) in which each term is the concatenation of the previous two.
Further, we define DA,B(n) to be the nth digit in the first term of FA,B that contains at least n digits.
@ -15,48 +15,29 @@ Example:
Let A=1415926535, B=8979323846. We wish to find DA,B(35), say.
The first few terms of FA,B are:
1415926535
8979323846
14159265358979323846
897932384614159265358979323846
14159265358979323846897932384614159265358979323846
The first few terms of FA,B are: 1415926535 8979323846 14159265358979323846 897932384614159265358979323846 14159265358979323846897932384614159265358979323846
Then DA,B(35) is the 35th digit in the fifth term, which is 9.
Now we use for A the first 100 digits of π behind the decimal point:
14159265358979323846264338327950288419716939937510
58209749445923078164062862089986280348253421170679
Now we use for A the first 100 digits of π behind the decimal point: 14159265358979323846264338327950288419716939937510 58209749445923078164062862089986280348253421170679
and for B the next hundred digits:
82148086513282306647093844609550582231725359408128
48111745028410270193852110555964462294895493038196 .
82148086513282306647093844609550582231725359408128 48111745028410270193852110555964462294895493038196 .
Find ∑n = 0,1,...,17   10n× DA,B((127+19n)×7n) .
</section>
Find ∑n = 0,1,...,17 10n× DA,B((127+19n)×7n) .
## Instructions
<section id='instructions'>
# --hints--
</section>
## Tests
<section id='tests'>
```yml
tests:
- text: <code>euler230()</code> should return 850481152593119200.
testString: assert.strictEqual(euler230(), 850481152593119200);
`euler230()` should return 850481152593119200.
```js
assert.strictEqual(euler230(), 850481152593119200);
```
</section>
# --seed--
## Challenge Seed
<section id='challengeSeed'>
<div id='js-seed'>
## --seed-contents--
```js
function euler230() {
@ -67,17 +48,8 @@ function euler230() {
euler230();
```
</div>
</section>
## Solution
<section id='solution'>
# --solutions--
```js
// solution required
```
</section>