Removed images and added text tables (#35900)

guide/english/sql/sql-count-function/index.md

@@ -17,38 +17,92 @@ For reference, here is the current data for all the rows in our example student
 ```sql
 select studentID, FullName, programOfStudy, sat_score from student; -- all records with fields of interest
 ```
-
-![image-1](https://github.com/SteveChevalier/guide-images/blob/master/count01.JPG?raw=true)
-
-This SQL statement provides a count of all rows.  Note that you can give the resulting COUNT column a name using "AS".
-
-```sql
-select count(*) AS studentCount from student; -- count of all records
+Result :
+```text
++-----------+------------------+----------------+-----------+
+| studentID | FullName         | programOfStudy | sat_score |
++-----------+------------------+----------------+-----------+
+|         1 | Monique Davis    | Literature     | 400       |
+|         2 | Teri Gutierrez   | Programming    | 800       |
+|         3 | Spencer Pautier  | Programming    | 1000      |    
+|         4 | Louis Ramsey     | Programming    | 1200      |     
+|         5 | Alvin Greene     | Photography    | 1400      |
+|         6 | Sophie Freeman   | Photography    | 1600      |
+|         7 | Maximo Smith     | Photography    | 1800      |
+|         8 | Michael Roach    | Literature     | 800       |
++-----------+------------------+----------------+-----------+
 ```
-![image-1](https://github.com/SteveChevalier/guide-images/blob/master/count02.JPG?raw=true)
 
-Here we get a count of students in each field of study.
+* This SQL statement provides a count of all rows.  Note that you can give the resulting COUNT column a name using "AS".
 
-```sql
- select programOfStudy, count(*) AS studentCount from the student table with a group by programOfStudy;
-```
-![image-1](https://github.com/SteveChevalier/guide-images/blob/master/count03.JPG?raw=true)
+  ```sql
+  select count(*) AS studentCount from student; -- count of all records
+  ```
+  Result :
+  ```text
+  +--------------+
+  | studentCount |
+  +--------------+
+  | 8            |
+  +--------------+
 
-Here we get a count of students with the same SAT scores.
-```sql
- select sat_score, count(*) AS studentCount from the student table with a group by sat_score;
-```
-![image-1](https://github.com/SteveChevalier/guide-images/blob/master/count04.JPG?raw=true)
+  ```
 
-Here is an example using the campaign funds table. This is a sum total of the dollars in each transaction and the number of contributions for each political party during the 2016 US Presidential Campaign.
+* Here we get a count of students in each field of study.
+
+  ```sql
+  select programOfStudy, count(*) AS studentCount from the student table with a group by programOfStudy;
+  ```
+  Result :
+  ```text
+  +----------------+--------------+
+  | programOfStudy | studentCount |
+  +----------------+--------------+
+  | Literature     | 2            |
+  | photography    | 3            |
+  | programming    | 3            |
+  +----------------+--------------+
+
+  ```
+
+* Here we get a count of students with the same SAT scores.
+  ```sql
+  select sat_score, count(*) AS studentCount from the student table with a group by sat_score;
+  ```
+  Result :
+  ```text
+  +-----------+--------------+
+  | sat_score | studentCount |
+  +-----------+--------------+
+  | 400       | 1            |
+  | 800       | 2            |
+  | 1000      | 1            |
+  | 1200      | 1            |
+  | 1400      | 1            |
+  | 1600      | 1            |
+  | 1800      | 1            |
+  +-----------+--------------+
+
+  ```
+
+* Here is an example using the campaign funds table. This is a sum total of the dollars in each transaction and the number of contributions for each political party during the 2016 US Presidential Campaign.
  
-```sql
-select Specific_Party, Election_Year, format(sum(Total_$),2) AS contribution$Total, count(*) AS numberOfContributions 
-from combined_party_data
-group by Specific_Party,Election_Year
-having Election_Year = 2016;
-```
+  ```sql
+  select Specific_Party, Election_Year, format(sum(Total_$),2) AS contribution$Total, count(*) AS numberOfContributions 
+  from combined_party_data
+  group by Specific_Party,Election_Year
+  having Election_Year = 2016;
+  ```
+  Result :
+  ```text
+  +----------------+---------------+--------------------+-----------------------+
+  | Specific_Party | Election_Year | contribution$Total | numberOfContributions |
+  +----------------+---------------+--------------------+-----------------------+
+  | DEMOCRATIC     | 2016          | 833,592,846.09     | 361                   |
+  | REPUBLICAN     | 2016          | 676,149,662.07     | 1247                  |
+  +----------------+---------------+--------------------+-----------------------+
+
+  ```
 
-![image-1](https://github.com/SteveChevalier/guide-images/blob/master/count05.JPG?raw=true)
 
 As with all of these things there is much more to it, so please see the manual for your database manager and have fun trying different tests yourself.