From 210a84b7e36e2d9cb3ed28bd6e5ed17957f4700c Mon Sep 17 00:00:00 2001
From: KevinatorTrainer5 <44285042+KevinatorTrainer5@users.noreply.github.com>
Date: Sat, 24 Nov 2018 11:25:29 +1100
Subject: [PATCH] Elaborated on more cases of factorising equations (#22494)
* Elaborated on more cases of factorising equations
-I decided to add other cases of factorising other algebraic equations that involves different values of the quadratic equation apart from 1
* Removing unnecessary
tags
---
.../mathematics/factoring-in-algebra/index.md | 23 +++++++++++++------
1 file changed, 16 insertions(+), 7 deletions(-)
diff --git a/guide/english/mathematics/factoring-in-algebra/index.md b/guide/english/mathematics/factoring-in-algebra/index.md
index 6c3e1b3e81..890b1d09bf 100644
--- a/guide/english/mathematics/factoring-in-algebra/index.md
+++ b/guide/english/mathematics/factoring-in-algebra/index.md
@@ -9,13 +9,22 @@ Factoring is how you take a quadratic in standard form and put it in factored fo
This method of factoring usually works best when a = 1. To do this when a = 1 you look at what two numbers add to equal b while also multiplying to c. Those two numbers will then be equal to d and t.
-#### Example 1:
-x2 + 2x + 1
-Here you have to look for two numbers that multiply to 1 and add to 2. Those two numbers are 1 and 1. Then you put those numbers into the factored form like this:
+#### Example 1:
+x2 + 2x + 1
+Here you have to look for two numbers that multiply to 1 and add to 2. Those two numbers are 1 and 1. Then you put those numbers into the factored form like this:
(x + 1)(x + 1)
-#### Example 2:
-x2 + 7x + 12
-Here you have to look for two numbers that multiply to 12 and add to 7. Those two numbers are 3 and 4. Then you put those numbers into the factored form like this:
-(x + 7)(x + 4).
+#### Example 2:
+x2 + 7x + 12
+Here you have to look for two numbers that multiply to 12 and add to 7. Those two numbers are 3 and 4. Then you put those numbers into the factored form like this:
+(x + 3)(x + 4).
+#### Example 3:
+2x2 + 3x + 1
+In some cases, the quadratic co-efficient, which is the value of a in ax2, can be greater than 1, where we need to consider how to create a number 3, through the combination of addition and multiplication with the factors of the quadratic co-efficient, and the co-efficient. So we consider the factors of 2 and 1 in '2' for the quadratic co-efficient, and the factors of 1 and 1 for the '1' in the co-efficient. We are required to multiply one factor of the quadratic co-efficient to another factor of the co-efficient, and consider the other case as well. So we multiply 2 from the quadratic co-efficient and 1 from the co-efficient, to receive a value of 2, while we multiply 1 from the quadratic co-efficient and 1 from the co-efficient, to receive a value of 1. Afterwards, we add the values of 2 and 1 to receive a value of 3, which corresponds to the linear co-efficient of 3x in the equation. Hence, you put these numbers into the factored form like this:
+(2x+1)(x+1).
+
+#### Example 4:
+6x2 + 11x + 4
+In some cases, the quadratic co-efficient, which is the value of a in ax2, can be greater than 1, where we need to consider how to create a number 11, through the combination of addition and multiplication with the factors of the quadratic co-efficient, and the co-efficient. So we consider the factors of 3 and 2 in '6' for the quadratic co-efficient, and the factors of 4 and 1 for the '4' in the co-efficient. We are required to multiply one factor of the quadratic co-efficient to another factor of the co-efficient, and consider the other case as well. So we multiply 2 from the quadratic co-efficient and 4 from the co-efficient, to receive a value of 8, while we multiply 3 from the quadratic co-efficient and 1 from the co-efficient, to receive a value of 3. Afterwards, we add the values of 8 and 3 to receive a value of 3, which corresponds to the linear co-efficient of 11x in the equation. Hence, you put these numbers into the factored form like this:
+(2x+1)(3x+4)