Added another clear example to probability (#21688)
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Manish Giri
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@ -8,7 +8,7 @@ Since there are **6** sides, this means that there is a **1 in 6** chance of any
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P(1) = P(2) = P(3) = P(4) = P(5) = P(6) = 1/6.
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Suppose we now take 2 fair dice. Since each of the six sides of die 1 can show face up with each of the six sides of die 2 there are 6 x 6 = 36 different possibilities and the chance of any combination occuring is therefore 1/36.
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Suppose we now take 2 fair dice. Since each of the six sides of die 1 can show face up with each of the six sides of die 2 there are 6 x 6 = 36 different possibilities and the chance of any combination occuring is therefore 1/36. If there are 3 die, there are 6 x 6 x 6 = 216 different possibilities, and so on with more die.
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If it doesn't matter in what order we look at the dice once we have rolled them, we have to look more carefully at the probabilities. For example, a 3 and a 5 can show up as 3 on die 1 and 5 on die 2 **or** 5 on die 1 and 3 on die 2 (2 combinations) so we can say that P(3,5 or 5,3) = 1/36 + 1/36 = 1/18.
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