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Punctuation and broken link (#18708)

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I fixed some inconsistent punctuation and some linked text that wasn't setup properly.
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benpeterdalley
2018-10-14 08:00:11 +11:00
committed by Quincy Larson
parent c97cd69ecd
commit 3ec1dfd5b6
1 changed files with 3 additions and 3 deletions
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client/src/pages/guide/english/python/if-elif-else-statements/index.md
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@ -5,7 +5,7 @@ title: If Elif Else Statements
## If Elif Else Statements ## If Elif Else Statements
The `if`/`elif`/`else` structure is a common way to control the flow of a program, allowing you to execute specific blocks of code depending on the value of some data. If the condition following the keyword `if` evaluates as `true`, the block of code will execute: The `if`/`elif`/`else` structure is a common way to control the flow of a program, allowing you to execute specific blocks of code depending on the value of some data. If the condition following the keyword `if` evaluates as `true`, the block of code will execute:
Note that parenthesis is not used before and after the condition check as in other languages . Note that parenthesis is not used before and after the condition check as in other languages.
```python ```python
if True: if True:
print('If block will execute!') print('If block will execute!')
@ -61,9 +61,9 @@ else:
*Note only the first condition that evaluates as `true` will execute. Even though `z > 6` is `true`, the `if/elif/else` block terminates after the first true condition. This means that an `else` will only execute if none of the conditions were `true`.* *Note only the first condition that evaluates as `true` will execute. Even though `z > 6` is `true`, the `if/elif/else` block terminates after the first true condition. This means that an `else` will only execute if none of the conditions were `true`.*
We can also create nested if's for decision making. Before preceding please refer to the href='https://guide.freecodecamp.org/python/code-blocks-and-indentation' target='_blank' rel='nofollow'>indentation guide once</a> before preceding. We can also create nested if's for decision making. Before preceding please refer to the <a href='https://guide.freecodecamp.org/python/code-blocks-and-indentation' target='_blank' rel='nofollow'>indentation guide once</a> before preceding.
Let's take an example of finding a number which is even and also greater than '10` Let's take an example of finding a number which is even and also greater than '10':
``` ```
python python
x = 34 x = 34