fix(curriculum): rework Project Euler 75 (#42066)
* fix: rework challenge to use argument in function * fix: add solution * fix: position block evenly between paragraphs
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@ -16,29 +16,47 @@ It turns out that 12 cm is the smallest length of wire that can be bent to form
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<strong>30 cm:</strong> (5,12,13)<br>
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<strong>30 cm:</strong> (5,12,13)<br>
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<strong>36 cm:</strong> (9,12,15)<br>
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<strong>36 cm:</strong> (9,12,15)<br>
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<strong>40 cm:</strong> (8,15,17)<br>
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<strong>40 cm:</strong> (8,15,17)<br>
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<strong>48 cm:</strong> (12,16,20)<br>
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<strong>48 cm:</strong> (12,16,20)<br><br>
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</div>
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</div>
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In contrast, some lengths of wire, like 20 cm, cannot be bent to form an integer sided right angle triangle, and other lengths allow more than one solution to be found; for example, using 120 cm it is possible to form exactly three different integer sided right angle triangles.
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In contrast, some lengths of wire, like 20 cm, cannot be bent to form an integer sided right angle triangle, and other lengths allow more than one solution to be found; for example, using 120 cm it is possible to form exactly three different integer sided right angle triangles.
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<div style='margin-left: 4em;'>
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<div style='margin-left: 4em;'>
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<strong>120 cm:</strong> (30,40,50), (20,48,52), (24,45,51)
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<strong>120 cm:</strong> (30,40,50), (20,48,52), (24,45,51)<br><br>
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</div>
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</div>
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Given that L is the length of the wire, for how many values of L ≤ 1,500,000 can exactly one integer sided right angle triangle be formed?
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Given that L is the length of the wire, for how many values of L ≤ `n` can exactly one, integer sided right angle, triangle be formed?
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# --hints--
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# --hints--
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`singularIntRightTriangles()` should return a number.
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`singularIntRightTriangles(48)` should return a number.
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```js
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```js
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assert(typeof singularIntRightTriangles() === 'number');
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assert(typeof singularIntRightTriangles(48) === 'number');
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```
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```
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`singularIntRightTriangles()` should return 161667.
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`singularIntRightTriangles(48)` should return `6`.
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```js
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```js
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assert.strictEqual(singularIntRightTriangles(), 161667);
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assert.strictEqual(singularIntRightTriangles(48), 6);
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```
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`singularIntRightTriangles(700000)` should return `75783`.
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```js
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assert.strictEqual(singularIntRightTriangles(700000), 75783);
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```
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`singularIntRightTriangles(1000000)` should return `107876`.
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```js
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assert.strictEqual(singularIntRightTriangles(1000000), 107876);
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```
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`singularIntRightTriangles(1500000)` should return `161667`.
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```js
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assert.strictEqual(singularIntRightTriangles(1500000), 161667);
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```
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```
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# --seed--
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# --seed--
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@ -46,16 +64,54 @@ assert.strictEqual(singularIntRightTriangles(), 161667);
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## --seed-contents--
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## --seed-contents--
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```js
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```js
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function singularIntRightTriangles() {
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function singularIntRightTriangles(n) {
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return true;
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return true;
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}
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}
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singularIntRightTriangles();
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singularIntRightTriangles(48);
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```
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```
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# --solutions--
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# --solutions--
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```js
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```js
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// solution required
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function singularIntRightTriangles(limit) {
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function euclidFormula(m, n) {
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return [m ** 2 - n ** 2, 2 * m * n, m ** 2 + n ** 2];
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}
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function gcd(numberA, numberB) {
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if (numberB === 0) {
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return numberA;
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}
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return gcd(numberB, numberA % numberB);
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}
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function notBothOdd(numberA, numberB) {
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return (numberA + numberB) % 2 === 1;
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}
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function areCoprime(numberA, numberB) {
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return gcd(numberA, numberB) === 1;
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}
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const trianglesWithPerimeter = new Array(limit + 1).fill(0);
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const mLimit = Math.sqrt(limit / 2);
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for (let m = 2; m < mLimit; m++) {
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for (let n = 1; n < m; n++) {
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if (notBothOdd(m, n) && areCoprime(m, n)) {
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const [sideA, sideB, sideC] = euclidFormula(m, n);
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const perimeter = sideA + sideB + sideC;
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let curPerimeter = perimeter;
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while (curPerimeter <= limit) {
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trianglesWithPerimeter[curPerimeter]++;
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curPerimeter += perimeter;
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}
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}
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}
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}
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return trianglesWithPerimeter.filter(trianglesCount => trianglesCount === 1)
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.length;
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}
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```
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```
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