Add a solution for Finders Keepers challenge (#35655)
* Add a solution for Finders Keepers challenge * Update link to markdown * fix: removed repl.it link * fix: made this the Intermediate Solution * fix: added correct Intermediate icon
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			@@ -1,7 +1,13 @@
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---
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title: Finders Keepers
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---
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## Problem Explanation
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 Remember to use <a>**`Read-Search-Ask`**</a> if you get stuck. Try to pair program  and write your own code 
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##  Problem Explanation:
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We need to return the element from an array that passes a function. Both the `function` and the `array` are passed into our function `findElement(arr, func)`.
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## Hint: 1
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@@ -16,7 +22,7 @@ Looking through the array can be done with a `for` loop.
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Do not forget, if none of the numbers in the array pass the test, it should return `undefined`.
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>*try to solve the problem now*
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## Basic Solution
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##  Basic Code Solution:
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```javascript
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function findElement(arr, func) {
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@@ -40,8 +46,18 @@ function findElement(arr, func) {
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* The pre-defined function already checks each number for us, so if it is "true", we return that num.
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* If none of the numbers in the array pass the function's test, we return undefined.
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##   Intermediate Code Solution:
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```javascript
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function findElement(arr, func) {
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  return arr.find(func);
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}
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```
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## Advanced Solution
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#### Relevant Links
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*   [Array.prototype.find](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/find)
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##  Advanced Code Solution:
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```javascript
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function findElement(arr, func) {
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@@ -55,3 +71,9 @@ function findElement(arr, func) {
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2. Use the function in the 2nd parameter as the callback function in arr.map()
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3. Acquire the index of the first number that meets the condition in the function.
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4. Use that index to display the first available number that meets the condition.
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##  NOTES FOR CONTRIBUTIONS:
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*    **DO NOT** add solutions that are similar to any existing solutions. If you think it is **_similar but better_**, then try to merge (or replace) the existing similar solution.
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*   Add an explanation of your solution.
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*   Categorize the solution in one of the following categories -- **Basic**, **Intermediate** and **Advanced**. 
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