fix(curriculum): clean-up Project Euler 241-260 (#42879)

* fix: clean-up Project Euler 241-260

* fix: typo

* Update curriculum/challenges/english/10-coding-interview-prep/project-euler/problem-255-rounded-square-roots.md

Co-authored-by: Tom <20648924+moT01@users.noreply.github.com>
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2021-07-16 12:21:45 +02:00
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@ -8,16 +8,24 @@ dashedName: problem-245-coresilience
# --description--
We shall call a fraction that cannot be cancelled down a resilient fraction. Furthermore we shall define the resilience of a denominator, R(d), to be the ratio of its proper fractions that are resilient; for example, R(12) = 411.
We shall call a fraction that cannot be cancelled down a resilient fraction.
The resilience of a number d > 1 is then φ(d)d 1 , where φ is Euler's totient function. We further define the coresilience of a number n > 1 as C(n)= n φ(n)n 1. The coresilience of a prime p is C(p) = 1p 1. Find the sum of all composite integers 1 &lt; n ≤ 2×1011, for which C(n) is a unit fraction.
Furthermore we shall define the resilience of a denominator, $R(d)$, to be the ratio of its proper fractions that are resilient; for example, $R(12) = \frac{4}{11}$.
The resilience of a number $d > 1$ is then $\frac{φ(d)}{d 1}$ , where $φ$ is Euler's totient function.
We further define the coresilience of a number $n > 1$ as $C(n) = \frac{n φ(n)}{n 1}$.
The coresilience of a prime $p$ is $C(p) = \frac{1}{p 1}$.
Find the sum of all composite integers $1 &lt; n ≤ 2 × {10}^{11}$, for which $C(n)$ is a unit fraction.
# --hints--
`euler245()` should return 288084712410001.
`coresilience()` should return `288084712410001`.
```js
assert.strictEqual(euler245(), 288084712410001);
assert.strictEqual(coresilience(), 288084712410001);
```
# --seed--
@ -25,12 +33,12 @@ assert.strictEqual(euler245(), 288084712410001);
## --seed-contents--
```js
function euler245() {
function coresilience() {
return true;
}
euler245();
coresilience();
```
# --solutions--