fix(curriculum): clean-up Project Euler 241-260 (#42879)

* fix: clean-up Project Euler 241-260

* fix: typo

* Update curriculum/challenges/english/10-coding-interview-prep/project-euler/problem-255-rounded-square-roots.md

Co-authored-by: Tom <20648924+moT01@users.noreply.github.com>
This commit is contained in:
gikf
2021-07-16 12:21:45 +02:00
committed by GitHub
parent b2059684ef
commit 67de105117
20 changed files with 272 additions and 154 deletions

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@ -12,9 +12,15 @@ Given a set of points on a plane, we define a convex hole to be a convex polygon
As an example, the image below shows a set of twenty points and a few such convex holes. The convex hole shown as a red heptagon has an area equal to 1049694.5 square units, which is the highest possible area for a convex hole on the given set of points.
For our example, we used the first 20 points (T2k1, T2k), for k = 1,2,…,20, produced with the pseudo-random number generator:
<img class="img-responsive center-block" alt="set of twenty points and convex holes on plane" src="https://cdn.freecodecamp.org/curriculum/project-euler/convex-holes.gif" style="background-color: white; padding: 10px;">
S0 = 290797 Sn+1 = Sn2 mod 50515093 Tn = ( Sn mod 2000 ) 1000
For our example, we used the first 20 points ($T_{2k 1}$, $T_{2k}$), for $k = 1, 2, \ldots, 20$, produced with the pseudo-random number generator:
$$\begin{align}
S_0 & = 290\\,797 \\\\
S_{n+1} & = {S_n}^2 \\; \text{mod} \\; 50\\,515\\,093 \\\\
T_n & = (S_n \\; \text{mod} \\; 2000) 1000
\end{align}$$
i.e. (527, 144), (488, 732), (454, 947), …
@ -22,10 +28,10 @@ What is the maximum area for a convex hole on the set containing the first 500 p
# --hints--
`euler252()` should return 104924.
`convexHoles()` should return `104924`.
```js
assert.strictEqual(euler252(), 104924);
assert.strictEqual(convexHoles(), 104924);
```
# --seed--
@ -33,12 +39,12 @@ assert.strictEqual(euler252(), 104924);
## --seed-contents--
```js
function euler252() {
function convexHoles() {
return true;
}
euler252();
convexHoles();
```
# --solutions--