diff --git a/curriculum/challenges/english/10-coding-interview-prep/project-euler/problem-461-almost-pi.md b/curriculum/challenges/english/10-coding-interview-prep/project-euler/problem-461-almost-pi.md
index 50a12c051c..10a83e63f8 100644
--- a/curriculum/challenges/english/10-coding-interview-prep/project-euler/problem-461-almost-pi.md
+++ b/curriculum/challenges/english/10-coding-interview-prep/project-euler/problem-461-almost-pi.md
@@ -8,26 +8,46 @@ dashedName: problem-461-almost-pi
 
 # --description--
 
-Let fn(k) = ek/n - 1, for all non-negative integers k.
+Let `f(k, n)` = $e^\frac{k}{n} - 1$, for all non-negative integers `k`.
 
-Remarkably, f200(6) + f200(75) + f200(89) + f200(226) = 3.141592644529… ≈ π.
+Remarkably, `f(6, 200) + f(75, 200) + f(89, 200) + f(226, 200)` = 3.1415926… ≈ π.
 
-In fact, it is the best approximation of π of the form fn(a) + fn(b) + fn(c) + fn(d) for n = 200.
+In fact, it is the best approximation of π of the form `f(a, 200) + f(b, 200) + f(c, 200) + f(d, 200)`.
 
-Let g(n) = a2 + b2 + c2 + d 2 for a, b, c, d that minimize the error: | fn(a) + fn(b) + fn(c) + fn(d) - π|
+Let `almostPi(n)` = a<sup>2</sup> + b<sup>2</sup> + c<sup>2</sup> + d<sup>2</sup> for a, b, c, d that minimize the error: $\lvert f(a,n) + f(b,n) + f(c,n) + f(d,n) - \Pi\rvert$
 
-(where |x| denotes the absolute value of x).
-
-You are given g(200) = 62 + 752 + 892 + 2262 = 64658.
-
-Find g(10000).
+You are given `almostPi(200)` = 6<sup>2</sup> + 75<sup>2</sup> + 89<sup>2</sup> + 226<sup>2</sup> = 64658.
 
 # --hints--
 
-`euler461()` should return 159820276.
+`almostPi` should be a function.
 
 ```js
-assert.strictEqual(euler461(), 159820276);
+assert(typeof almostPi === 'function')
+```
+
+`almostPi` should return a number.
+
+```js
+assert.strictEqual(typeof almostPi(10), 'number');
+```
+
+`almostPi(29)` should return `1208`.
+
+```js
+assert.strictEqual(almostPi(29), 1208);
+```
+
+`almostPi(50)` should return `4152`.
+
+```js
+assert.strictEqual(almostPi(50), 4152);
+```
+
+`almostPi(200)` should return `64658`.
+
+```js
+assert.strictEqual(almostPi(200), 64658);
 ```
 
 # --seed--
@@ -35,16 +55,99 @@ assert.strictEqual(euler461(), 159820276);
 ## --seed-contents--
 
 ```js
-function euler461() {
-
+function almostPi(n) {
+  
   return true;
 }
-
-euler461();
 ```
 
 # --solutions--
 
 ```js
-// solution required
+function almostPi(n) {
+
+  // Find all possible values where f(k, n) <= PI
+  const f = [];
+  let max = 0;
+  while (1) {
+    let current = Math.exp(max / n) - 1;
+
+    if (current > Math.PI) break;
+
+    f.push(current);
+    ++max;
+  }
+
+  // Get all pairs where f[i] + f[j] <= PI
+  const pairs = [];
+  for (let i = 0; i < max; ++i) {
+    for (let j = 0; j < max; ++j) {
+      if (f[i] + f[j] > Math.PI) break;
+      pairs.push(f[i] + f[j]);
+    }
+  }
+
+  // Sort all values
+  pairs.sort((a, b) => a - b);
+
+  // Optimal Value for (a + b)
+  let left = 0;
+  // Optimal Value for (c + d)
+  let right = 0;
+  // minimum error with Math.abs(a + b - Math.PI)
+  let minError = Math.PI;
+
+  // Binary Search for the best match
+  for (let i = 0; i < pairs.length; ++i) {
+    let current = pairs[i];
+    let need = Math.PI - current;
+
+    if (need < current) break;
+
+    let match;
+    for (let i = 1; i < pairs.length; ++i) {
+      if (pairs[i] > need) {
+        match = i;
+        break;
+      }
+    }
+
+    let error = Math.abs(need - pairs[match]);
+    if (error < minError)
+    {
+      minError = error;
+      left = i;
+      right = match;
+    }
+
+    --match;
+    error = Math.abs(need - pairs[match]);
+    if (error < minError) {
+      minError = error;
+      left = i;
+      right = match;
+    }
+  }
+
+  let a, b, c, d;
+
+  OuterLoop1:
+  for (a = 0; a < max; ++a) {
+    for (b = a; b < max; ++b) {
+      if (pairs[left] == f[a] + f[b]) {
+        break OuterLoop1;
+      }
+    }
+  }
+
+  OuterLoop2:
+  for (c = 0; c < max; ++c) {
+    for (d = c; d < max; ++d) {
+      if (pairs[right] == f[c] + f[d]) {
+        break OuterLoop2;
+      }
+    }
+  }
+  return a*a + b*b + c*c + d*d;
+}
 ```