diff --git a/curriculum/challenges/_meta/basic-javascript/meta.json b/curriculum/challenges/_meta/basic-javascript/meta.json
index 568e2d9633..2e9185d571 100644
--- a/curriculum/challenges/_meta/basic-javascript/meta.json
+++ b/curriculum/challenges/_meta/basic-javascript/meta.json
@@ -440,13 +440,13 @@
       "587d7b7e367417b2b2512b21",
       "Use Multiple Conditional (Ternary) Operators"
     ],
-    [
-      "5cc0bd7a49b71cb96132e54c",
-      "Use Recursion to Create a Range of Numbers"
-    ],
     [
       "5cd9a70215d3c4e65518328f",
       "Use Recursion to Create a Countdown"
+    ],    
+    [
+      "5cc0bd7a49b71cb96132e54c",
+      "Use Recursion to Create a Range of Numbers"
     ]
   ],
   "helpRoom": "HelpJavaScript",
diff --git a/curriculum/challenges/english/02-javascript-algorithms-and-data-structures/basic-javascript/use-recursion-to-create-a-countdown.md b/curriculum/challenges/english/02-javascript-algorithms-and-data-structures/basic-javascript/use-recursion-to-create-a-countdown.md
index 08d1534e29..3b9d5ab89e 100644
--- a/curriculum/challenges/english/02-javascript-algorithms-and-data-structures/basic-javascript/use-recursion-to-create-a-countdown.md
+++ b/curriculum/challenges/english/02-javascript-algorithms-and-data-structures/basic-javascript/use-recursion-to-create-a-countdown.md
@@ -8,15 +8,34 @@ forumTopicId: 305925
 ## Description
 <section id='description'>
 
-Continuing from the previous challenge, we provide you another opportunity to create a recursive function to solve a problem.
+In a [previous challenge](/learn/javascript-algorithms-and-data-structures/basic-javascript/replace-loops-using-recursion), you learned how to use recursion to replace a for loop. Now, let's look at a more complex function that returns an array of consecutive integers starting with <code>1</code> through the number passed to the function.
+
+As mentioned in the previous challenge, there will be a <dfn>base case</dfn>.  The base case tells the recursive function when it no longer needs to call itself.  It is a simple case where the return value is already known. There will also be a <dfn>recursive call</dfn> which executes the original function with different arguments. If the function is written correctly, eventually the base case will be reached.
+
+For example, say you want to write a recursive function that returns an array containing the numbers <code>1</code> through <code>n</code>.  This function will need to accept an argument, <code>n</code>, representing the final number. Then it will need to call itself with progressively smaller values of <code>n</code> until it reaches <code>1</code>. You could write the function as follows:
+
+```javascript
+function countup(n) {
+  if (n < 1) {
+    return [];
+  } else {
+    const countArray = countup(n - 1);
+    countArray.push(n);
+    return countArray;
+  }
+}
+console.log(countup(5)); // [ 1, 2, 3, 4, 5 ]
+```
+
+At first, this seems counterintuitive since the value of `n` <em>decreases</em>, but the values in the final array are <em>increasing</em>.  This happens because the push happens last, after the recursive call has returned.  At the point where `n` is pushed into the array, `count(n - 1)` has already been evaluated and returned `[1, 2, ..., n - 1]`.
 
 </section>
 
 ## Instructions
 <section id='instructions'>
 
-We have defined a function called <code>countdown</code> with two parameters.  The function should take an array in the <code>myArray</code> parameter and append the numbers n through 1 based on the <code>n</code> parameter.  
-For example, calling this function with <code>n = 5</code> will pad the array with the numbers <code>[5, 4, 3, 2, 1]</code> inside of it.
+We have defined a function called <code>countdown</code> with one parameter (<code>n</code>).  The function should use recursion to return an array containing the integers <code>n</code> through <code>1</code> based on the <code>n</code> parameter. If the function is called with a number less than 1, the function should return an empty array. 
+For example, calling this function with <code>n = 5</code> should return the array <code>[5, 4, 3, 2, 1]</code>.
 Your function must use recursion by calling itself and must not use loops of any kind.
 
 </section>
@@ -26,13 +45,13 @@ Your function must use recursion by calling itself and must not use loops of any
 
 ``` yml
 tests:
-  - text: After calling <code>countdown(myArray, -1)</code>, myArray should be empty.
-    testString: assert.isEmpty(padArray([], -1));
-  - text: After calling <code>countdown(myArray, 10)</code>, myArray should contain <code>[10, 9, 8, 7, 6, 5, 4, 3, 2, 1]</code>
-    testString: assert.deepStrictEqual(padArray([], 10), [10, 9, 8, 7, 6, 5, 4, 3, 2, 1]);
-  - text: After calling <code>countdown(myArray, 5)</code>, myArray should contain <code>[5, 4, 3, 2, 1]</code>
-    testString: assert.deepStrictEqual(padArray([], 5), [5, 4, 3, 2, 1]);
-  - text: Your code should not rely on any kind of loops (<code>for</code> or <code>while</code> or higher order functions such as <code>forEach</code>, <code>map</code>, <code>filter</code>, or <code>reduce</code>.).
+  - text: <code>countdown(-1)</code> should return an empty array.
+    testString: assert.isEmpty(countdown(-1));
+  - text: <code>countdown(10)</code> should return <code>[10, 9, 8, 7, 6, 5, 4, 3, 2, 1]</code>
+    testString: assert.deepStrictEqual(countdown(10), [10, 9, 8, 7, 6, 5, 4, 3, 2, 1]);
+  - text: <code>countdown(5)</code> should return <code>[5, 4, 3, 2, 1]</code>
+    testString: assert.deepStrictEqual(countdown(5), [5, 4, 3, 2, 1]);
+  - text: Your code should not rely on any kind of loops (<code>for</code>, <code>while</code> or higher order functions such as <code>forEach</code>, <code>map</code>, <code>filter</code>, and <code>reduce</code>).
     testString: assert(!removeJSComments(code).match(/for|while|forEach|map|filter|reduce/g));
   - text: You should use recursion to solve this problem.
     testString: assert(removeJSComments(countdown.toString()).match(/countdown\s*\(.+\)\;/));
@@ -49,10 +68,10 @@ tests:
 
 
 //Only change code below this line
-function countdown(myArray, n){
+function countdown(n){
   return;
 }
-
+console.log(countdown(5)); // [5, 4, 3, 2, 1]
 ```
 
 </div>
@@ -62,11 +81,6 @@ function countdown(myArray, n){
 
 ```js
 const removeJSComments = str => str.replace(/\/\*[\s\S]*?\*\/|\/\/.*$/gm, '');
-function padArray(arr, n){
-  countdown(arr, n);
-  return arr;
-}
-
 ```
 
 </div>
@@ -78,14 +92,8 @@ function padArray(arr, n){
 
 ```js
 //Only change code below this line
-function countdown(myArray, n){
-  if(n <= 0){
-    return;
-  }
-  else{
-    myArray.push(n);
-    countdown(myArray, n - 1);
-  }
+function countdown(n){
+   return n < 1 ? [] : [n].concat(countdown(n - 1));
 }
 ```
 
diff --git a/curriculum/challenges/english/02-javascript-algorithms-and-data-structures/basic-javascript/use-recursion-to-create-a-range-of-numbers.english.md b/curriculum/challenges/english/02-javascript-algorithms-and-data-structures/basic-javascript/use-recursion-to-create-a-range-of-numbers.english.md
index 05b47d3c82..d0bada33b6 100644
--- a/curriculum/challenges/english/02-javascript-algorithms-and-data-structures/basic-javascript/use-recursion-to-create-a-range-of-numbers.english.md
+++ b/curriculum/challenges/english/02-javascript-algorithms-and-data-structures/basic-javascript/use-recursion-to-create-a-range-of-numbers.english.md
@@ -8,25 +8,7 @@ forumTopicId: 301180
 ## Description
 <section id='description'>
 
-In a [previous challenge](/learn/javascript-algorithms-and-data-structures/basic-javascript/replace-loops-using-recursion), you learned how to use recursion to replace a for loop. Now, let's look at a more complex function that returns an array of consecutive integers starting with <code>1</code> through the number passed to the function.
-
-As mentioned in the previous challenge, there will be a <dfn>base case</dfn>.  The base case tells the recursive function when it no longer needs to call itself.  It is a simple case where the return value is already known. There will also be a <dfn>recursive call</dfn> which executes the original function with different arguments. If the function is written correctly, eventually the base case will be reached.
-
-For example, say you want to write a recursive function that returns an array containing the numbers 1 through n.  This function will need to accept an argument <code>n</code> representing the final number. Then it will need to call itself with progressively smaller values of <code>n</code> until it reaches 1. You could write the function as follows:
-
-```js
-function count(n) {
-  if (n === 1) {
-    return [1];
-  } else {
-    var numbers = count(n - 1); 
-    numbers.push(n);
-    return numbers;
-  }
-}
-```
-
-At first this is counterintuitive since the value of `n` <em>decreases</em>, but the values in the final array are <em>increasing</em>.  This happens because the push happens last, after the recursive call has returned.  At the point where `n` is pushed into the array, `count(n - 1)` has already been evaluated and returned `[1, 2, ..., n - 1]`.
+Continuing from the previous challenge, we provide you another opportunity to create a recursive function to solve a problem.
 
 </section>