diff --git a/guide/english/python/len-function/index.md b/guide/english/python/len-function/index.md
index 9d525143f8..b9a5a657e5 100644
--- a/guide/english/python/len-function/index.md
+++ b/guide/english/python/len-function/index.md
@@ -12,19 +12,32 @@ It takes one argument, `x`. This argument may be a sequence (such as a string, b
This function returns the number of elements in the argument which is passed to the `len()` function.
## Code Sample
-
- list1 = [123, 'xyz', 'zara'] # list
- print(len(list1)) # prints 3 as there are 3 elements in the list1
-
- str1 = 'basketball' # string
- print(len(str1)) # prints 10 as the str1 is made of 10 characters
-
- tuple1 = (2, 3, 4, 5) # tuple
- print(len(tuple1)) # prints 4 as there are 4 elements in the tuple1
-
- dict1 = {'name': 'John', 'age': 4, 'score': 45} # dictionary
- print(len(dict1)) # prints 3 as there are 3 key and value pairs in the dict1
+```py
+ >>> list1 = [123, 'xyz', 'zara'] # list
+ >>> print(len(list1)) # prints 3 as there are 3 elements in the list1
+ 3
+```
+```py
+ >>> str1 = 'basketball' # string
+ >>> print(len(str1)) # prints 10 as the str1 is made of 10 characters
+ 10
+```
+```py
+ >>> tuple1 = (2, 3, 4, 5) # tuple
+ >>> print(len(tuple1)) # prints 4 as there are 4 elements in the tuple1
+ 4
+```
+```py
+ >>> dict1 = {'name': 'John', 'age': 4, 'score': 45} # dictionary
+ >>> print(len(dict1)) # prints 3 as there are 3 key and value pairs in the dict1
+ 3
+```
+```py
+ >>> d2=[[1,2,3],[3,4,5],[5,6,7,2]] # 2 dimensional list or a list of lists
+ >>> print(len(d2)) #prints 3 because there are 3 different lists in the outer list.
+ 3
+```
 Run Code
-Official Docs
\ No newline at end of file
+Official Docs