fix(curriculum) replace single-line blocks with multi-line blocks for… (#41526)

* fix(curriculum) replace single-line blocks with multi-line blocks for issue 51418

Data visualization and Coding Interview Prep portions.

* Update execute-a-markov-algorithm.md

Implemented as inline code blocks as discussed

* Adding missed blocks

* Last file added

curriculum/challenges/english/10-coding-interview-prep/rosetta-code/execute-a-markov-algorithm.md

@@ -40,13 +40,7 @@ the shop -> my brother
 a never used -> .terminating rule
 </pre>
 
-Sample text of:
-
-`I bought a B of As from T S.`
-
-Should generate the output:
-
-`I bought a bag of apples from my brother.`
+Sample text of `I bought a B of As from T S.` should generate the output `I bought a bag of apples from my brother.`
 
 **Ruleset 2:**
 
@@ -61,13 +55,7 @@ the shop -> my brother
 a never used -> .terminating rule
 </pre>
 
-Sample text of:
-
-`I bought a B of As from T S.`
-
-Should generate:
-
-`I bought a bag of apples from T shop.`
+Sample text of `I bought a B of As from T S.` should generate `I bought a bag of apples from T shop.`
 
 **Ruleset 3:**
 
@@ -86,13 +74,7 @@ the shop -> my brother
 a never used -> .terminating rule
 </pre>
 
-Sample text of:
-
-`I bought a B of As W my Bgage from T S.`
-
-Should generate:
-
-`I bought a bag of apples with my money from T shop.`
+Sample text of `I bought a B of As W my Bgage from T S.` should generate `I bought a bag of apples with my money from T shop.`
 
 **Ruleset 4:**
 
@@ -128,13 +110,7 @@ _1 -> 1
 _+_ ->
 </pre>
 
-Sample text of:
-
-`_1111*11111_`
-
-should generate the output:
-
-`11111111111111111111`
+Sample text of `_1111*11111_` should generate the output `11111111111111111111`
 
 **Ruleset 5:**
 
@@ -164,13 +140,7 @@ B1 -> 1B
 1C1 -> H11
 </pre>
 
-This ruleset should turn
-
-`000000A000000`
-
-into
-
-`00011H1111000`
+This ruleset should turn `000000A000000` into `00011H1111000`
 
 # --hints--
 

curriculum/challenges/english/10-coding-interview-prep/rosetta-code/loop-over-multiple-arrays-simultaneously.md

@@ -12,11 +12,15 @@ Loop over multiple arrays and create a new array whose $i^{th}$ element is the c
 
 For this example, if you are given this array of arrays:
 
-`[ ["a", "b", "c"], ["A", "B", "C"], [1, 2, 3] ]`
+```js
+[ ["a", "b", "c"], ["A", "B", "C"], [1, 2, 3] ]
+```
 
 the output should be:
 
-`["aA1","bB2","cC3"]`
+```js
+["aA1","bB2","cC3"]
+```
 
 # --instructions--
 

curriculum/challenges/english/10-coding-interview-prep/rosetta-code/sort-disjoint-sublist.md

@@ -14,7 +14,9 @@ Make your function work with the following list of values and set of indices:
 
 <code>values: [7, <b>6</b>, 5, 4, 3, 2, <b>1</b>, <b>0</b>]</code>
 
-`indices(0-based): {6, 1, 7}`
+```js
+indices(0-based): {6, 1, 7}
+```
 
 Where the correct result would be:
 

curriculum/challenges/english/10-coding-interview-prep/rosetta-code/top-rank-per-group.md

@@ -32,7 +32,9 @@ testData1 = [
 
 One could rank top 10 employees in each department by calling:
 
-`topRankPerGroup(10, testData1, 'dept', 'salary')`
+```js
+topRankPerGroup(10, testData1, 'dept', 'salary')
+```
 
 Given the following data:
 
@@ -48,7 +50,9 @@ testData2 = [
 
 One could rank the top-rated movie in each genre by calling:
 
-`topRankPerGroup(1, testData2, 'genre', 'rating')`
+```js
+topRankPerGroup(1, testData2, 'genre', 'rating')
+```
 
 The function should return an array with an array for each group containing the top `n` objects.