diff --git a/guide/english/mathematics/simplifying-square-roots/index.md b/guide/english/mathematics/simplifying-square-roots/index.md
index 43f3c0cca2..3706ac4055 100644
--- a/guide/english/mathematics/simplifying-square-roots/index.md
+++ b/guide/english/mathematics/simplifying-square-roots/index.md
@@ -3,42 +3,45 @@ title: Simplifying Square Roots
---
## Simplifying Square Roots
-Simplied Radical form:
-Let's say you have the radical SQRT(363), and you need to simplify it into both a nicer looking number and a number that you can use in specific calculations, to do this by trying to find perfect squares within the radical.
+Let's say you have the radical √363, and you need to simplify it into a both, simplest number, and a number that you can use in specific calculations, where we can do this by trying to find perfect squares within the radical.
-So, it's a fact that SQRT(x*y) = SQRT(x) + SQRT(y)
-and this fact allows us to seperate the SQRT(243) into pieces
+So, it's a fact that:
-but first, we need to find a factor of 363, tha would allow us to pull a perfect square from it.
-Perfect squares include 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144... because each of them has a sqare root that is a whole number
+√(x×y) = √x × √y
-Now, factors of 363 are:
-1, 3, 11, 33, 121 and 363
+and this fact allows us to understand that we can seperate the √xy into two separate radicals, √x and √y.
-If you look, you can see that 121 is among that list, 121*3 is 363, and we can change the radical to show that:
-SQRT(363) = SQRT(121*3)
- = SQRT(121)*SQRT(3)
-And we can take the square root of 121, and make it a whole number:
- = 11*Sqrt(3)
-And that's your radical.
+But first, we need to find a factor of 363, that would allow us to pull a perfect square from it.
+Perfect square numbers include: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144 etc. ,as each of them can become a whole number if these numbers were square rooted.
+Now, factors of 363 are: 1, 3, 11, 33, 121 and 363.
+If you look, you can see that 121 is among that list, 121×3 is 363, and we can change the radical to show that:
+
+√363 = √(121×3) = √121 × √3
+
+And we can take the square root of 121, where we can turn it into a whole number:
+
+= 11 × √3
+
+Hence, 11√3 is the square root number of 363.
+
+## Simplifying Square roots in the Denominator:
+Lets' say you have the expression:
+
+2⁄√5
+
+And you wanted to simplify this by removing the radical from the denominator, well you can do this by multiplying this fraction by:
+
+√5⁄√5
-Simplifying Square roots in the denominator:
-Lets' say you have the expression:
- 2
--------
-SQRT(5)
-And you wanted to simplify this by removing the radical from the denominator, well you can do this by multiplying this fraction by:
-SQRT(5)
--------
-SQRT(5)
Which is equal to one, and you get:
- 2 SQRT(5) 2 x SQRT(5)
-------- x ------- = ----------- because a square root multiplied by itself is the number in the square, the denominator is now a
-SQRT(5) SQRT(5) 5 whole number, not a radical. The radical still exists in the top, but this is fine in most cases.
+
+2⁄√5 × √5⁄√5
+
+= 2√5⁄5
+
+because a square root multiplied by itself is the number in the square, the denominator is now a whole number, not a radical anymore. The radical still exists in the top, but this is fine in most cases, as the value itself is still exact.
#### More Information:
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