From ad39f4a8d9af12e97b005e3db35cbce12a6f4714 Mon Sep 17 00:00:00 2001 From: KevinatorTrainer5 <44285042+KevinatorTrainer5@users.noreply.github.com> Date: Sun, 18 Nov 2018 14:53:17 +1100 Subject: [PATCH] Equation symbol changes and formatting changes (#22049) * Equation symbol changes and formatting changes -Initially, SQRT(value) does not actually create a square root symbol, so I decided to use replace SQRT( ) with √ next to the number, which has successfully created the square root symbol to the left of the number. -Given that the information of the article was unorganized through jumbled information, I decided to use the paragraph tag,

, to make the article have an organized structure. -I also used the biggest headline tag,

, to outline the topics of square roots -Given that '-----' was not an effective method of creating fractions, I decided to use the fraction slash tag, "⁄", the superscript element, , and the subscript element, , in order to create suitable fractions * Removing unnecessary coding and editing content -I just double checked this content, and realized that there were a couple of mistakes such as an extra heading, putting a square root as sqrt(3) instead of √3, and adding unnecessary paragraph tags instead of extra spaces. --- .../simplifying-square-roots/index.md | 59 ++++++++++--------- 1 file changed, 31 insertions(+), 28 deletions(-) diff --git a/guide/english/mathematics/simplifying-square-roots/index.md b/guide/english/mathematics/simplifying-square-roots/index.md index 43f3c0cca2..3706ac4055 100644 --- a/guide/english/mathematics/simplifying-square-roots/index.md +++ b/guide/english/mathematics/simplifying-square-roots/index.md @@ -3,42 +3,45 @@ title: Simplifying Square Roots --- ## Simplifying Square Roots -Simplied Radical form: -Let's say you have the radical SQRT(363), and you need to simplify it into both a nicer looking number and a number that you can use in specific calculations, to do this by trying to find perfect squares within the radical. +Let's say you have the radical √363, and you need to simplify it into a both, simplest number, and a number that you can use in specific calculations, where we can do this by trying to find perfect squares within the radical. -So, it's a fact that SQRT(x*y) = SQRT(x) + SQRT(y) -and this fact allows us to seperate the SQRT(243) into pieces +So, it's a fact that: -but first, we need to find a factor of 363, tha would allow us to pull a perfect square from it. -Perfect squares include 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144... because each of them has a sqare root that is a whole number +√(x×y) = √x × √y -Now, factors of 363 are: -1, 3, 11, 33, 121 and 363 +and this fact allows us to understand that we can seperate the √xy into two separate radicals, √x and √y. -If you look, you can see that 121 is among that list, 121*3 is 363, and we can change the radical to show that: -SQRT(363) = SQRT(121*3) - = SQRT(121)*SQRT(3) -And we can take the square root of 121, and make it a whole number: - = 11*Sqrt(3) -And that's your radical. +But first, we need to find a factor of 363, that would allow us to pull a perfect square from it. +Perfect square numbers include: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144 etc. ,as each of them can become a whole number if these numbers were square rooted. +Now, factors of 363 are: 1, 3, 11, 33, 121 and 363. +If you look, you can see that 121 is among that list, 121×3 is 363, and we can change the radical to show that: + +√363 = √(121×3) = √121 × √3 + +And we can take the square root of 121, where we can turn it into a whole number: + += 11 × √3 + +Hence, 11√3 is the square root number of 363. + +## Simplifying Square roots in the Denominator: +Lets' say you have the expression: + +2⁄√5 + +And you wanted to simplify this by removing the radical from the denominator, well you can do this by multiplying this fraction by: + +√5⁄√5 -Simplifying Square roots in the denominator: -Lets' say you have the expression: - 2 -------- -SQRT(5) -And you wanted to simplify this by removing the radical from the denominator, well you can do this by multiplying this fraction by: -SQRT(5) -------- -SQRT(5) Which is equal to one, and you get: - 2 SQRT(5) 2 x SQRT(5) -------- x ------- = ----------- because a square root multiplied by itself is the number in the square, the denominator is now a -SQRT(5) SQRT(5) 5 whole number, not a radical. The radical still exists in the top, but this is fine in most cases. + +2⁄√5 × √5⁄√5 + += 2√5⁄5 + +because a square root multiplied by itself is the number in the square, the denominator is now a whole number, not a radical anymore. The radical still exists in the top, but this is fine in most cases, as the value itself is still exact. #### More Information: - -