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chore(i18n,curriculum): update translations (#43795)

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curriculum/challenges/chinese/10-coding-interview-prep/algorithms/find-the-symmetric-difference.md
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---
id: a3f503de51cf954ede28891d
title: Find the Symmetric Difference
title: 找到对称差异
challengeType: 5
forumTopicId: 301611
dashedName: find-the-symmetric-difference
@ -8,77 +8,77 @@ dashedName: find-the-symmetric-difference
# --description--
The mathematical term <dfn>symmetric difference</dfn> (`△` or `⊕`) of two sets is the set of elements which are in either of the two sets but not in both. For example, for sets `A = {1, 2, 3}` and `B = {2, 3, 4}`, `A △ B = {1, 4}`.
两个集合的数学术语 <dfn>对称差异</dfn> （`△` 或 `⊕`）是指存在于两个集合中的任意一个集合，但不同时存在于两个集合中的元素的集。 例如集合 `A = {1, 2, 3}` 和 `B = {2, 3, 4}`，那么 `A △ B = {1, 4}`。
Symmetric difference is a binary operation, which means it operates on only two elements. So to evaluate an expression involving symmetric differences among *three* elements (`A △ B △ C`), you must complete one operation at a time. Thus, for sets `A` and `B` above, and `C = {2, 3}`, `A △ B △ C = (A △ B) △ C = {1, 4} △ {2, 3} = {1, 2, 3, 4}`.
对称差异是一种二元操作，这意味着它只能在两个元素上操作。 所以要评估一个涉及*三个*元素的表达式（`A △ B △ C`），你必须一次完成一个操作。 因此，对于上述 `A` 和 `B` 两个集合，如果 `C = {2, 3}`，那么 `A △ B △ C = (A △ B) △ C = {1, 4} △ {2, 3} = {1, 2, 3, 4}`。
# --instructions--
Create a function that takes two or more arrays and returns an array of their symmetric difference. The returned array must contain only unique values (*no duplicates*).
创建一个接受两个或更多数组的函数，并返回所提供数组的对称差异。 结果数组必须仅包含唯一值（ *不重复* ）。
# --hints--
`sym([1, 2, 3], [5, 2, 1, 4])` should return `[3, 4, 5]`.
`sym([1, 2, 3], [5, 2, 1, 4])` 应该返回 `[3, 4, 5]` 。
```js
assert.sameMembers(sym([1, 2, 3], [5, 2, 1, 4]), [3, 4, 5]);
```
`sym([1, 2, 3], [5, 2, 1, 4])` should contain only three elements.
`sym([1, 2, 3], [5, 2, 1, 4])` 应该仅包含三个元素。
```js
assert.equal(sym([1, 2, 3], [5, 2, 1, 4]).length, 3);
```
`sym([1, 2, 3, 3], [5, 2, 1, 4])` should return `[3, 4, 5]`.
`sym([1, 2, 3, 3], [5, 2, 1, 4])` 应返回 `[3, 4, 5]` 。
```js
assert.sameMembers(sym([1, 2, 3, 3], [5, 2, 1, 4]), [3, 4, 5]);
```
`sym([1, 2, 3, 3], [5, 2, 1, 4])` should contain only three elements.
`sym([1, 2, 3, 3], [5, 2, 1, 4])` 应仅包含三个元素。
```js
assert.equal(sym([1, 2, 3, 3], [5, 2, 1, 4]).length, 3);
```
`sym([1, 2, 3], [5, 2, 1, 4, 5])` should return `[3, 4, 5]`.
`sym([1, 2, 3], [5, 2, 1, 4, 5])` 应该返回 `[3, 4, 5]`。
```js
assert.sameMembers(sym([1, 2, 3], [5, 2, 1, 4, 5]), [3, 4, 5]);
```
`sym([1, 2, 3], [5, 2, 1, 4, 5])` should contain only three elements.
`sym([1, 2, 3], [5, 2, 1, 4, 5])` 应仅包含三个元素。
```js
assert.equal(sym([1, 2, 3], [5, 2, 1, 4, 5]).length, 3);
```
`sym([1, 2, 5], [2, 3, 5], [3, 4, 5])` should return `[1, 4, 5]`
`sym([1, 2, 5], [2, 3, 5], [3, 4, 5])` 应该返回 `[1, 4, 5]` 。
```js
assert.sameMembers(sym([1, 2, 5], [2, 3, 5], [3, 4, 5]), [1, 4, 5]);
```
`sym([1, 2, 5], [2, 3, 5], [3, 4, 5])` should contain only three elements.
`sym([1, 2, 5], [2, 3, 5], [3, 4, 5])` 应仅包含三个元素。
```js
assert.equal(sym([1, 2, 5], [2, 3, 5], [3, 4, 5]).length, 3);
```
`sym([1, 1, 2, 5], [2, 2, 3, 5], [3, 4, 5, 5])` should return `[1, 4, 5]`.
`sym([1, 1, 2, 5], [2, 2, 3, 5], [3, 4, 5, 5])` 应该返回 `[1, 4, 5]`。
```js
assert.sameMembers(sym([1, 1, 2, 5], [2, 2, 3, 5], [3, 4, 5, 5]), [1, 4, 5]);
```
`sym([1, 1, 2, 5], [2, 2, 3, 5], [3, 4, 5, 5])` should contain only three elements.
`sym([1, 1, 2, 5], [2, 2, 3, 5], [3, 4, 5, 5])` 应仅包含三个元素。
```js
assert.equal(sym([1, 1, 2, 5], [2, 2, 3, 5], [3, 4, 5, 5]).length, 3);
```
`sym([3, 3, 3, 2, 5], [2, 1, 5, 7], [3, 4, 6, 6], [1, 2, 3])` should return `[2, 3, 4, 6, 7]`.
`sym([3, 3, 3, 2, 5], [2, 1, 5, 7], [3, 4, 6, 6], [1, 2, 3])` 应该返回 `[2, 3, 4, 6, 7]` 。
```js
assert.sameMembers(
@ -87,7 +87,7 @@ assert.sameMembers(
);
```
`sym([3, 3, 3, 2, 5], [2, 1, 5, 7], [3, 4, 6, 6], [1, 2, 3])` should contain only five elements.
`sym([3, 3, 3, 2, 5], [2, 1, 5, 7], [3, 4, 6, 6], [1, 2, 3])` 应该只包含五个元素。
```js
assert.equal(
@ -96,7 +96,7 @@ assert.equal(
);
```
`sym([3, 3, 3, 2, 5], [2, 1, 5, 7], [3, 4, 6, 6], [1, 2, 3], [5, 3, 9, 8], [1])` should return `[1, 2, 4, 5, 6, 7, 8, 9]`.
`sym([3, 3, 3, 2, 5], [2, 1, 5, 7], [3, 4, 6, 6], [1, 2, 3], [5, 3, 9, 8], [1])`应返回`[1, 2, 4, 5, 6, 7, 8, 9]` 。
```js
assert.sameMembers(
@ -112,7 +112,7 @@ assert.sameMembers(
);
```
`sym([3, 3, 3, 2, 5], [2, 1, 5, 7], [3, 4, 6, 6], [1, 2, 3], [5, 3, 9, 8], [1])` should contain only eight elements.
`sym([3, 3, 3, 2, 5], [2, 1, 5, 7], [3, 4, 6, 6], [1, 2, 3], [5, 3, 9, 8], [1])` 应仅包含八个元素。
```js
assert.equal(