fix: update guide hint to properly declare regex (#34625)
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		| @@ -17,8 +17,8 @@ localeTitle: إعادة استخدام الأنماط باستخدام مجمو | ||||
|  | ||||
| إذا كنا سنترجم التعبير المعتاد حرفياً ، فسيبدو شيئًا كالتالي: | ||||
|  | ||||
|  `let re = /(test)\s\1;  | ||||
|  let literalRe = /test\stest;  | ||||
|  `let re = /(test)\s\1/;  | ||||
|  let literalRe = /test\stest/;  | ||||
| `  | ||||
|  | ||||
| كل من `rea` و `literalRe` تطابق نفس الشيء. | ||||
|   | ||||
| @@ -19,8 +19,8 @@ let testString = "test test test "; | ||||
| 如果我们要正面翻译正则表达式,它看起来像这样: | ||||
|  | ||||
| ```js | ||||
| let re = /(test)\s\1;  | ||||
|  let literalRe = /test\stest;  | ||||
| let re = /(test)\s\1/;  | ||||
|  let literalRe = /test\stest/;  | ||||
| ``` | ||||
|  | ||||
| `rea`和`literalRe`都会匹配相同的东西。 | ||||
|   | ||||
| @@ -12,11 +12,11 @@ let result = reRegex.test(testString); | ||||
| ``` | ||||
| `result` will match only `test test` because `\1` in this example stands for the same text as most recently matched by the 1st capturing group `(test)`. | ||||
|  | ||||
| If we were to lierally translate the regex, it would look something like this: | ||||
| If we were to literally translate the regex, it would look something like this: | ||||
|  | ||||
| ```js | ||||
| let re = /(test)\s\1; | ||||
| let literalRe = /test\stest; | ||||
| let re = /(test)\s\1/; | ||||
| let literalRe = /test\stest/; | ||||
| ``` | ||||
| Both `rea` and `literalRe` would match the same thing. | ||||
|  | ||||
|   | ||||
| @@ -19,8 +19,8 @@ let testString = "test test test "; | ||||
| Se fôssemos traduzir literalmente o regex, seria algo como isto: | ||||
|  | ||||
| ```js | ||||
| let re = /(test)\s\1;  | ||||
|  let literalRe = /test\stest;  | ||||
| let re = /(test)\s\1/;  | ||||
|  let literalRe = /test\stest/;  | ||||
| ``` | ||||
|  | ||||
| Ambos `rea` e `literalRe` combinariam com a mesma coisa. | ||||
|   | ||||
| @@ -19,8 +19,8 @@ let testString = "test test test "; | ||||
| Если бы мы должны были перевести регулярное выражение, это выглядело бы примерно так: | ||||
|  | ||||
| ```js | ||||
| let re = /(test)\s\1;  | ||||
|  let literalRe = /test\stest;  | ||||
| let re = /(test)\s\1/;  | ||||
|  let literalRe = /test\stest/;  | ||||
| ``` | ||||
|  | ||||
| И `rea` и `literalRe` будут соответствовать одному и тому же. | ||||
|   | ||||
| @@ -19,8 +19,8 @@ let testString = "test test test "; | ||||
| Si tuviéramos que traducir literalmente la expresión regular, se vería algo así: | ||||
|  | ||||
| ```js | ||||
| let re = /(test)\s\1;  | ||||
|  let literalRe = /test\stest;  | ||||
| let re = /(test)\s\1/;  | ||||
|  let literalRe = /test\stest/;  | ||||
| ``` | ||||
|  | ||||
| Tanto `rea` como `literalRe` coincidirían con la misma cosa. | ||||
|   | ||||
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