diff --git a/guide/english/mathematics/2-by-2-determinants/index.md b/guide/english/mathematics/2-by-2-determinants/index.md
index b15ace4ba1..01d2ac13e0 100644
--- a/guide/english/mathematics/2-by-2-determinants/index.md
+++ b/guide/english/mathematics/2-by-2-determinants/index.md
@@ -15,12 +15,17 @@ Given a matrix A, the determinant of A (written as |A|) is given by the followin
 ## Properties of (2x2) determinants
 
 The rows and vectors of a 2 by 2 matrix can be associated with points on a cartesian plane, such that each row forms a 2D vector. These two vectors form a parallelogram, as shown in the image below.
-PROOF:
-Let the vectors be M(a,b),N(c,d) originating from origin in a 2-D plane with an angle (*theta*>0) between them(head of one vector touching tail of another vector). But in here it doesn't matter because sin(theta)=sin(2(pi)-theta). Then the other point is P(a+c,b+d). The area of the parallelogram is perpendicular distance from one point say N(c,d) to the base vector, M(a,b) multiplied by the length of the base vector, |M(a,b)|. The parallelogram consists of two triangles hence, the area is two times of a triangle. 
-Let the perpendicular distance be h
-h=|N(c,d)|* sin(*theta*(angle between two vectors))
-b=|M(a,b)|
-Area=h * b
+
+### Proof
+
+Let the vectors be M(a,b),N(c,d) originating from origin in a 2-D plane with an angle (θ>0) between them (head of one vector aligning with tail of another vector). But in here it doesn't matter because sin(θ)=sin(2π-θ). Then the other point is P(a+c,b+d). The area of the parallelogram is perpendicular distance from one point say N(c,d) to the base vector, M(a,b) multiplied by the length of the base vector, |M(a,b)|. The parallelogram consists of two triangles hence, the area is two times of a triangle. 
+
+Let the perpendicular distance be h.
+
+Then:
+- h=|N(c,d)| * sin(θ)
+- b=|M(a,b)|
+- Area = h * b
 
 The absolute value of the determinant is equal to the area of the parallelogram.