From d37f5a7751177ff1507dbdd91546b720859f711a Mon Sep 17 00:00:00 2001 From: Andrew Mackie Date: Thu, 7 Mar 2019 18:46:51 -0800 Subject: [PATCH] Fixed typos (#27202) --- .../english/mathematics/completing-the-square/index.md | 10 +++++----- 1 file changed, 5 insertions(+), 5 deletions(-) diff --git a/guide/english/mathematics/completing-the-square/index.md b/guide/english/mathematics/completing-the-square/index.md index 24ac0c4152..88e54dbe1d 100644 --- a/guide/english/mathematics/completing-the-square/index.md +++ b/guide/english/mathematics/completing-the-square/index.md @@ -13,7 +13,7 @@ A quadratic equation generally takes the form: ax2 + bx + c 
ax2 + bx = -c
2. Make the coefficient of x2 equal to 1 by dividing both sides of the equation by a so that we now have:
-
x2 + (b/a)x = - (c/a)
+
x2 + (b/a)x = -(c/a)
3. Next, add the square of half of the coefficient of the x-term to both sides of the equation: 
x2 + (b/a)x  + (b/2a)2 = (b/2a)2 - (c/a)
@@ -21,14 +21,14 @@ A quadratic equation generally takes the form: ax2 + bx + c 4. Completing the square on the Left Hand Side and simplifying the Right Hand Side of the above equation, we have: 
(x + b/2a)2 = (b2/4a2) - (c/a)
-5. Further simplpfying the Right Hand Side, -
(x + b/2a)2 = (b2 - 4ac)/4a2
+5. Further simplifying the Right Hand Side, +
(x + b/2a)2 = (b2 - 4ac) ÷ 4a2
6. Finding the square root of both sides of the equation, -
x + b/2a = √(b2 - 4ac) ÷ 2a
+
x + b/2a = ±((b2 - 4ac)½ ÷ 2a)
7. By making x the subject of our formula, we are able to solve for its value completely: -
x = -b ± √(b2 - 4ac) ÷ 2a
+
x = (-b ± (b2 - 4ac)½) ÷ 2a
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