diff --git a/curriculum/challenges/english/08-data-analysis-with-python/numpy/initialize-array-problem.md b/curriculum/challenges/english/08-data-analysis-with-python/numpy/initialize-array-problem.md
index d2ae486862..d9ec566b72 100644
--- a/curriculum/challenges/english/08-data-analysis-with-python/numpy/initialize-array-problem.md
+++ b/curriculum/challenges/english/08-data-analysis-with-python/numpy/initialize-array-problem.md
@@ -20,42 +20,44 @@ question:
     What is another way to produce the following array?
 
     ```py
-    [[1. 1. 1. 1. 1.]
-    [1. 0. 0. 0. 1.]
-    [1. 0. 9. 0. 1.]
-    [1. 0. 0. 0. 1.]
-    [1. 1. 1. 1. 1.]]
+    [[0. 0. 0. 0. 0. 0. 0.]
+    [0. 1. 1. 1. 1. 1. 0.]
+    [0. 1. 1. 1. 1. 1. 0.]
+    [0. 1. 1. 5. 1. 1. 0.]
+    [0. 1. 1. 1. 1. 1. 0.]
+    [0. 1. 1. 1. 1. 1. 0.]
+    [0. 0. 0. 0. 0. 0. 0.]]
     ```
 
   answers:
     - |
       ```py
-      output = np.ones((5, 5))
+      output = np.ones((7, 7))
 
-      z = np.zeros((3, 3))
-      z[1, 1] = 9
+      z = np.zeros((5, 5))
+      z[2, 2] = 5
+
+      output[1:1, -1:-1] = z
+      ```
+    - |
+      ```py
+      output = np.zeros((7,7))
+
+      z = np.ones((5, 5))
+      z[2, 2] = 5
 
       output[1:-1, 1:-1] = z
       ```
     - |
       ```py
-      output = np.ones((5, 5))
+      output = np.ones((7, 7))
 
-      z = np.zeros((3, 3))
-      z[1, 1] = 9
+      z = np.zeros((5, 5))
+      z[3, 3] = 5
 
-      output[1:3, 1:3] = z
+      output[1:-1, 1:-1] = z
       ```
-    - |
-      ```py
-      output = np.ones((5, 5))
-
-      z = np.zeros((3, 3))
-      z[1, 1] = 9
-
-      output[4:1, 4:1] = z
-      ```
-  solution: 1
+  solution: 2
 ````
 
 </section>